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I personally understand what you are saying... everyone has a teacher like that at least once in their schooling.
Doing two-step equations can sometimes be tricky, even if you understand the topic pretty well. All two-step equations are: equations that require two objectives to solve for the variable (That's why it's called a <em>two-step </em>equation).
There are multi-step equations...but let's take one bite at a time.
First, let's establish one simple rule:
Anything you do to one side of the algebraic equation, you must do to the other side for the equation to remain true.
For example:
So, we have this just chillin' out with the
. When trying to solve for a variable, this is usually not what we want. The
needs to be alone for us to know what
equals.
For the first step of getting alone, we can add
on each side of the equation to cancel out the
on the variable's side. Remember to do it on both sides of the equation!
becomes
Did you see what I did there? All I did was basically add to
and
. The equation remains equal, but using that simple rule, we were able to get one step closer to isolating the
in the equation.
To continue...
turns into
<em>(This is because the
and the
cancel out.)</em>
Now we have
This next step should look familiar to you (assuming you already know how to solve for one-step equations, I'll keep it short and sweet).
Now, since is the same as saying
times
, we can do the opposite of multiplication...which is <em>division, </em>like so:
The 's will cancel each other out and
simplifies to
.
Awesome! Looks like we solved our two-step equation!
In the equation: ,
Some things to remember:
- What ever you do to one side of the equation, you must do to the other.
- You want to apply the opposite sign of the number you are trying to cancel out of the equation while isolating the
.
- Never make it harder than it needs to be. It is called a two-step equation for a reason, multi-step requires more than two...but wait until you have to work those before you start using fifty different ways to solve the equation.
Hope I was able to help you out! Have a good one, and God bless!
<em>Also, if you are confused about something I answered, or I may be incorrect, feel free to let me know!</em>
Considering the sum and the product of the roots of the quadratic equation, it is found that the numeric value of the expression is given as follows:
A quadratic equation is defined as follows:
The roots of the equation are given as follows:
The sum of the roots is given as follows:
The product of the roots is given as follows:
In the context of this problem, the product is of 4, as hence:
c/a = 4
c = 4a.
The coefficients are in an arithmetic progression, hence:
- b = a + d. (d is the common difference of the sequence).
- c = a + 2d.
We have that c = 4a, hence:
4a = a + 2d
2d = 3a
d = 1.5a.
Hence coefficient b is calculated as follows:
b = a + d = a + 1.5a = 2.5a.
Then the sum of the roots is given as follows:
More can be learned about quadratic equations at brainly.com/question/24737967
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