Answer : 
Given expression is 
To make perfect square trinominal we use completing the square method
In completing the square method we add and subtract the half of square of coefficient of middle term
Here coefficient of middle term is -7
Half of -7 is 
Square of
is
=
So the expression becomes
that gives perfect square trinomial
Hence , the value of 'c' is
Answer:
276923 square inches
Step-by-step explanation:
I probably got it wrong to be honest
Answer:
A. About 4,900 ft
Step-by-step explanation:
We want h such that ...
5 = 10·ln(h) -80
8.5 = ln(h) . . . . . . . add 80, divide by 10
e^8.5 = h ≈ 4914.8 . . . . take the antilog
h ≈ 4900 . . . . feet
Answer:
The radian measure of the angle drawn in standard position that corresponds with the ray containing the coordinate point
is approximately
radians.
Step-by-step explanation:
With respect to origin, the coordinate point belongs to the third quadrant, which comprises the family of angles from
to
. The angle in standard position can be estimated by using the following equivalence:



The radian measure of the angle drawn in standard position that corresponds with the ray containing the coordinate point
is approximately
radians.