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2 years ago

Help please! Picture is attached

Mathematics

1 answer:

Sladkaya [172]2 years ago

4 0

Answer:

They are going different directions. Different

They have the same function but reversed in directions. Same

Step-by-step explanation:

You might be interested in

A group of 72 children completed a survey on what kind of sport they like. The choices were: Chess, Swimming, and Football. Ever

Svetach [21]

Answer:

19/72

Step-by-step explanation:

To calculate the probability that a randomly-chosen child from this group likes either Chess or Swimming but not Football?

We already know the number that liked chess only which is 10, we have to solve for those that liked swimming only which is

8+7+16+x = 40

x which represent swimming only is

40-31 = 9

Thus probability = 10/72 + 9/72 = 19/72

3 0

3 years ago

Find f(1/3) if f(n)=3n

tia_tia [17]

F(n)=3n
f(1/3)=3(1/3)
f(1/3)=1

Hope I didn't mess up for your sake

8 0

2 years ago

Please answer the questions: A, B, C , and D , please, Will give u lots of points!!!!

Korvikt [17]

Answer:

This is the worksheet answer

3 0

2 years ago

Roll one fair, six-sided die, numbered 1 through 6. Let A be the event you will roll an even number. Let B be the event you will

11111nata11111 [884]

Answer:

a) not independent

b) not mutually exclusive

Step-by-step explanation:

Given:

- A 6 sided die is rolled

- Event A is rolling an even number

- Event B is rolling a prime number

Find

- (a) Are A and B independent events?

- (b) Are A and B mutually exclusive events?

Solution:

- We will find the probability of each event:

set(Even number: A) = {2, 4, 6} = 3 outcomes

set(Prime number: B) = {2 , 3, 5} = 3 outcomes

- The probabilities are:

P(A) = 3/6 = 0.5

P(B) = 3/6 = 0.5

- For Event A and B to be independent then the following condition must match:

P ( A & B ) = P(A)*P(B)

set (A&B) = {2} = 1 outcome

P(A&B) = 1/6

1 / 6 = 0.5*0.5

1/6 = 0.25 ...... NOT INDEPENDENT

- For Event A and B to be mutually exclusive then the following condition must match:

P(A&B) = 0

P(A&B) = 1/6

Hence, we can say the events are NOT MUTUALLY EXCLUSIVE

7 0

3 years ago

Can't figure out this problem can anyone help if so thank you

Virty [35]

Answer:

10th term of the sequence = 0.537

Step-by-step explanation:

First three terms of the sequence are → 5, 4, $\frac{16}{5}$ ..........

Ratio of 2nd and 1st term of the sequence = $\frac{4}{5}$

Ratio of 3rd and 2nd term of the sequence = $\frac{\frac{16}{5} }{4}$

= $\frac{4}{5}$

Therefore, ratio between every successive term to the previous term is common.

Common ratio 'r' = $\frac{4}{5}$

First term of the sequence 'a' = 5

nth term of a geometric sequence = $a(r)^n$

Therefore, nth term of the given term will be $T_n=5(\frac{4}{5})^n$

Now we have to find the 10 term of the given sequence.

For n = 10,

$T_{10}=5(\frac{4}{5})^{10}$

= 0.53687

≈ 0.537

Therefore, 10th term of the sequence is 0.537

7 0

2 years ago