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castortr0y [4]
3 years ago
6

What structure is part of an echinoderms water vascular system?

Biology
1 answer:
lilavasa [31]3 years ago
4 0

The water vascular system controls the tube feet hydraulically through a complex of fluid filled canals and reservoirs. Unlike other echinoderms, the madreporite of the holothuroideans is located internally below the pharynx and opens to the coelom instead of the outside world.

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¿como se divide la fotosíntesis?
kolbaska11 [484]

Answer:

El proceso de la fotosíntesis se divide en dos etapas, la primera llamada "Lumínica" o fotodependiente y la segunda "Oscura" o fotoindependiente.

Explanation:

6 0
3 years ago
If the earth was not spinning, there could still be a
mote1985 [20]

I think its the Diurnal Cycle.

5 0
3 years ago
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The half-life of carbon-14 is 5730 years. Radiocarbon dating can not be used to estimate the age of objects up to about 50,000 o
Nataly [62]

Answer:

False

Explanation:

it can be used to date stuff up to about 50000 years, so i'd say that its halfly false, so false is correct :)

7 0
3 years ago
Why is it important that a plant's phloem extends into its leaves?
Cerrena [4.2K]
The correct answer among the choices listed above is option C. It is important that a plant's phloem extends into its leaves because the phloem <span>collects the sugars made during photosynthesis and carries them around the plant. Hope this answers the question.</span>
7 0
3 years ago
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A rooster with gray feathers is mated with a hen of the same phenotype. Among their offspring, 15 chicks are gray, 6 are black,
m_a_m_a [10]

Answer:

Alleles for feather colour exhibit incomplete dominance or co-dominance.

50% gray offspring + 50% black offspring

Explanation:

<em>It means that the alleles for feather colour in the hen exhibit incomplete dominance or co-dominance over one another.</em>

Assuming the allele for white colour is B, white colour will be b while the heterozygote Bb gives the gray phenotype.

Gray rooster + gray hen = 15 gray chicks, 6 black chicks and 8 white chicks.

15:6:8 is roughly 2:1:1 which is phenotypic ratio obtainable from crossing two heterozygous individuals as pointed out by Mendel.

Bb   x   Bb = 1BB, 2Bb, and 1bb

Crossing the gray rooster (Bb) with a black hen (bb):

Bb   x   bb = Bb, Bb, bb, and bb

          = 2Bb (gray):2bb (black)

50% of the offspring will be gray while the remaining 50% will be black.

7 0
3 years ago
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