Answer:
Probability that the son will be:
color-blind = 1/2
blue eyed = 1/8
blue eyed and color-blind = 1/16
Explanation:
Mother : BbXcX
Father : BbXY
Colorblindness is X linked recessive trait hence will be caused when the son has XcY genotype.
XcX X XY :
Xc X
X XcX XX
Y XcY XY
Half of the sons will have normal vision and other half will be colorblind hence, there is 1/2 probability that the son will be colorblind.
Eye color is autosomal trait and blue color will be produced when the child has bb genotype.
Bb X Bb :
B b
B BB Bb
b Bb bb
1/4 of the children will have blue eyes. Since half of the children are expected to be males, 1/4 * 1/2 = 1/8 sons are expected to have blue eyes.
Probability of a son being blue eyed and color blind will be :
1/8 * 1/2 = 1/16
Cell division happens twice during meiosis. One starting cell can produce for gametes (eggs or sperm.) In each round of division, cells go through four phases called prophase, metaphase, anaphase, and telophase.
prophase During prophase the chromosomes become visible as paired chromatids and the nuclear envelope disappears. This phase includes reduction division, which is where the number of chromosomes is decreased from 46 (diploid) to 23 (haploid.)
metaphase This is where the 23 remaining chromosomes become attached to the spindle fibers.
anaphase During this phase, the chromosomes move away from each other to one or the other pole of the spindle fiber.
telophase In which the chromatids or chromosomes move to opposite ends of the cell and two nuclei are formed.
interphase This is a resting period.
Answer:
Eye colour
Explanation:
Eye colour is passed by your parents, what ever colour they have will determine what the child would have
If it was like two brown eyes the child would have brown eyes
If it was two different colours whatever colour which is more dominent will detirmen the colour of the child's eye