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Amiraneli [1.4K]
4 years ago
12

Please help with this one math question?

Mathematics
1 answer:
oksano4ka [1.4K]4 years ago
8 0
JK=  \sqrt{JL^2+KL^2 -2\cdot JL \cdot KL \cdot cos62^o}\\\\ {} \ \ \ \ \  =\sqrt{3^2+5^2 -2\cdot 3 \cdot 5 \cdot 0.4695} \\\\ {} \ \ \ \ \  =\sqrt{34 -14.085}\\\\ {} \ \ \ \ \  = \sqrt{19.915} \\\\ {} \ \ \ \ \  \approx 4.5 \ \  mm
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Solve 4(2x-3)=6x+2<br> I don't understand the steps pls
Marysya12 [62]

Answer: x = 7

Step-by-step explanation:

4(2x-3) = 6x+2   <--distribute the 4

8x - 12 = 6x + 2   <---add 12 to both sides

8x = 6x + 14    <--- subrtract 6x from both sides

2x = 14    <--- divide by two

x = 7

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3 years ago
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sashaice [31]
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3 years ago
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Shkiper50 [21]

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6 0
3 years ago
gabriella rents bikes for $13 plus $7 per hour. Eduardo paid $27 to rent a bike for how many hours did he rent the bike?
e-lub [12.9K]

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5 0
3 years ago
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suter [353]
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Translaitng <span>8 units to the right you get points A'(2,-6), B'(2,-4), C'(6,-4) and D'(4,-6) that are exactly vertices of quadrilateral A'B'C'D'.
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6 0
3 years ago
Read 2 more answers
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