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charle [14.2K]
3 years ago
8

PLEASE HELP! :( What is the surface area of the right cone below?

Mathematics
2 answers:
AleksandrR [38]3 years ago
6 0

Answer:

<em>A≈606.32</em>

Step-by-step explanation:

you need to use this equation: A=πr(r+h^2+r^2) to figure it out...

just plug your length, height, and radius in, and u have ur answer!!

ur answer shud be <em>A≈606.32</em>

<em />

Hope this helps!!

DaniilM [7]3 years ago
3 0

The surface area of the right cone is 176π sq unit. Option C.

Step-by-step explanation:

Given,

The radius (r) of the cone = 8 unit

Slant height (l) = 14 unit

To find the surface area of the right cone.

Formula

The surface area of the right cone = πrl+πr² sq unit

Now,

The surface area of the right cone = π×8×14+π×8² sq unit

= 112π+64π = 176π sq unit.

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Step-by-step explanation:

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2 years ago
If triangle RST and triangle XYZ are similar, which of these equations must be true?
Delicious77 [7]

Answer: A

Step-by-step explanation:

If they are similar, that means the proportions for corresponding sides will be the same.

          I personally ignore the picture and use the labels of "triangle RST and triangle XYZ" that the problem gives <em>because</em> the XYZ picture is not lined up with the similarity it has with RST.

(A) says that side ST is corresponding with side YZ,

          [] Triangle R<u>ST</u> and triangle X<u>YZ</u>

          -> Correct

(A) also says that side RT is corresponding with size XZ,

          [] Triangle <u>R</u>S<u>T</u> and triangle <u>X</u>Y<u>Z</u>

          -> Correct

               This means that option A is the correct answer.

4 0
2 years ago
The lunch lady has 12 pounds of lasagna left over.
bogdanovich [222]

Answer:

12

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5 0
2 years ago
Pleasee helppp insert two arithnetic means between -5 and 1
Salsk061 [2.6K]

Answer:

a₂ = -3

a₃  = -1

Step-by-step explanation:

We have to  insert two arithmetic means between -5 and 1

Let a₁ and b₂ be the two arithmetic means between -5 and 1

-5, a₂, a₃, 1

Here,

  • a₄ = 1
  • a₁ = -5

We know that the nth term of an Arithmetic sequence

aₙ = a₁ + (n-1)d

a₄ = -5 + (4-1)d

1 = -5 + 3d    

1  + 5 = 3d

3d = 6

Dividing both sides by 2

d = 2

Also

a₂ = a₁ + (2-1)d

a₂ = -5 + d

a₂ = -5 + 2          ∵ d = 2

a₂  = -3

a₃ = a₁ + (3-1)d

a₃  = -5 + 2d

a₃  = -5 + 2(2)   ∵ d = 2

a₃  = -5 + 4

a₃  = -1

Thus,

a₂ = -3

a₃  = -1

Thus, the sequence becomes:

-5, -3, -3, 1

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