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Dahasolnce [82]
3 years ago
9

76=8x can u solve this pls​

Mathematics
2 answers:
ohaa [14]3 years ago
5 0

Answer:

x = 9.5

Step-by-step explanation:

I hope this helps you out!

Nitella [24]3 years ago
3 0

Answer:

x=9.5

Step-by-step explanation:

Divide both sides by 8

76/8=8/8

x=9.5

I hope this helped you, have a great day! :)

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Jane and john shared some money such that jane got 4 times as much money as john. What fraction of money did john get ?​
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1/5

Step-by-step explanation:

let's assume the share John gets to be x

John: x

jane: 4x

therefore there total will be 5x

x/5x=0.2 or 1/5

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A recent CBS News survey reported that 64% of adults felt the U.S. Treasury should continue making pennies. Suppose we select a
enyata [817]

Complete Question

A recent CBS News survey reported that 64% of adults felt the U.S. Treasury should continue making pennies. Suppose we select a sample of 18 adults.

a-1. How many of the 18 would we expect to indicate that the Treasury should continue making pennies

a-2) What is the standard deviation?

a-3) What is the likelihood that exactly 3 adults would indicate the Treasury should continue making pennies?

Answer:

a-1 \= x = 11 .52

a-2  \sigma  = 2.036

a-3 P(3) =  4.7*10^{-5}

Step-by-step explanation:

From the question we are told that

  The sample size is  n =  18

  The proportion of adult that  felt the U.S. Treasury should continue making pennies is p =  0.64

 The proportion of adult that  feel otherwise is

q = 1- p = 1-0.64 = 0.36

 The mean is mathematically evaluated as

      \= x =  n * p

substituting values

  \= x = 18 * 0.64

   \= x = 11 .52

The standard deviation is mathematically represented as

       \sigma  =  \sqrt{ npq}

substituting values

      \sigma  =  \sqrt{18 * 0.64 * 0.36}

      \sigma  = 2.036

The likelihood that 3 adult would indicate  the Treasury should continue making pennies is mathematically evaluated as

    P(3) = \left  n} \atop  \right. C_3  (p)^{3} * (q)^{n-3}

Now

    \left  n} \atop  \right. C_3 =  \frac{n! }{[n-3] ! 3!}

substituting values

    \left  n} \atop  \right. C_3 =  \frac{18! }{[15] ! 3!}

    \left  n} \atop  \right. C_3 =  \frac{18 * 17 * 16 * 15! }{[15] ! (3 *2 *1 )}

   \left  n} \atop  \right. C_3 =  \frac{18 * 17 * 16 }{ (3 *2 *1 )}

   \left  n} \atop  \right. C_3 =  816    

So

    P(3) =  816 * (0.64 )^3 * (0.36 )^{18-3}

    P(3) =  4.7*10^{-5}

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3 years ago
For each ordered pair in the table, how does the second number compare to the first number... can yall tell me I need to turn it
spayn [35]

Answer:

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