42 - (-25) 33 - (-77) 44 + (-18)
1 answer:
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Answer:
Independence chi-square test
Step-by-step explanation:
The Chi-Square Test for independence is a type of statistical hypothesis test that is used to determine the existence of an association or relationship between nominal or categorical variables
The chi-square is given by the following formula;
The number of participants = 80
The number that assigned a verdict of guilty = 27
The number that assigned a verdict of not guilty by reason of self defense = 49
The number that assigned a verdict of not guilty by reason of insanity = 4
Independence Chi Square test
The table of values is presented as follows;
Expected Value = (Row sum * Column Sum)/(Grand Total)
Expected Value for Guilty = 27 × 80/80 = 27
Expected Value for Self Defense = 49 × 80/80 = 49
Expected value for Insanity = 4 × 80/80 = 4
Answer:
0
Step-by-step explanation:
Let X to be a random variable that looks a binomial distribution which denoted the number of employees out of the 281 who earn the prevailing minimum wage or less
The sample size n = 281
The population parameter p = 5% = 0.05
Using normal approximation for the mean.
The standard deviation is:
By using continuity correction; the sample mean x is:
x = 30 - 0.5
x = 29.5
The z statistic test can now be as follows:
Z = 4.23
Thus, the probability that company A will get a discount is
P(X ≥ 30) = P(Z >4.23)
= 1 - P(Z < 4.23)
By using the Excel function for the z score 4.23 i.e. "=1 - NORMSDIST(4.23)" we get;
= 0.0000