R(t) = integral of r'(t) = integral of ti + e^tj + te^tk = 1/2t^2i + e^tj + (te^t - e^t)k + c
r(0) = j - k + c = i + j + k
c = i + 2k
Therefore, r(t) = (1/2t^2 + 1)i + e^tj + (te^t - e^t + 2)k
Good morning
21 + 3q < 3(13 - q)
21+ 3q < 39 - 3q Here it was -3q and it was on the left side. However when you are switching it to another terms that looks like it you must change the sign as well.
3q + 3q < 39 - 21 Here I bring the common terms together.
6q < 18
Divide both sides by 6
6q/6 < 18/6
q < 3

Step-by-step explanation:
the plus sign would have a line under it
Answer:
x=6
Step-by-step explanation:
3+x=9
-3 -3
x=6
Step-by-step explanation:
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