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Vesnalui [34]
3 years ago
7

Simplify b^2/3a^-4 what's the answer

Mathematics
2 answers:
Andru [333]3 years ago
6 0
Combine like terms. Is there a picture for this?
tatiyna3 years ago
3 0

Answer:

Simplify b^2/3a^-4 what's the answer

Step-by-step explanation:

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Please help
EleoNora [17]

Answer:

Step-by-step explanation:

(5⅔)/4 = (17/3)/4 = 17/12

7 0
3 years ago
A rectangle has a length of 11 meters less than 10 times its width. If the area of the rectangle is 9888 square meters, find the
kobusy [5.1K]

Step-by-step explanation:

The Length ,

L

=

284

f

t

.

Explanation:

Given:

Rectangle

Area,

A

=

8804

f

t

2

let W bet he width of the rectangle

L be the length of the rectangle

L

=

10

W

−

26

E

q

u

a

t

i

o

n

1

substitute to

e

q

u

a

t

i

o

n

2

A

=

(

L

)

(

W

)

e

q

u

a

t

i

o

n

2

A

=

(

10

W

−

26

)

(

W

)

8804

=

(

10

W

−

26

)

(

W

)

factor

8804

=

2

(

5

W

−

13

)

(

W

)

divide both sides by 2

4402

=

(

5

W

−

13

)

(

W

)

4402

=

5

W

2

−

13

W

transposing 4402 to the right side of the equation

0

=

5

W

2

−

13

W

−

4402

by quadratic formula

W

=

−

(

−

13

)

+

√

(

−

13

)

2

−

4

(

5

)

(

−

4402

)

2

(

5

)

W

=

[

13

+

√

169

+

88040

]

10

W

=

13

+

(

√

88209

)

10

W

=

13

+

297

10

W

=

310

10

W

=

31

ft

Thus ,

L

=

10

W

−

26

=

10

(

31

)

−

26

L

=

284

f

t

.

answer

W

=

−

(

−

13

)

−

√

−

(

−

13

2

)

−

4

(

5

)

(

−

4402

)

2

(

5

)

this is discarded since this will yield a negative

8 0
3 years ago
What the range of 80,84,86,87,90,91,92,94,100
inessss [21]

Answer:

20

pls mark brainliest if possible

Step-by-step explanation:

the range is the difference between the values of the largest and smallest values. You can figure this out with subtraction.

Largest number: 100

Smallest number: 80

Range: 20

6 0
3 years ago
TunsAXP what is the value of x when x = 13
Advocard [28]

Answer:

the value of x would be 13

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Verify cot x sec^4x=cotx +2tanx +tan^3x
Tanzania [10]

Answer:

See explanation

Step-by-step explanation:

We want to verify that:

\cot(x)  \:  { \sec}^{4} x =  \cot(x) + 2 \tan(x)   +  { \tan}^{3} x

Verifying from left, we have

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \: ( 1 +  { \tan}^{2} x )^{2}

Expand the perfect square in the right:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \: ( 1 +  { 2\tan}^{2} x  + { \tan}^{4} x)

We expand to get:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  \cot(x){ 2\tan}^{2} x  +\cot(x) { \tan}^{4} x

We simplify to get:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  2 \frac{ \cos(x) }{\sin(x) ) }  \times  \frac{{ \sin}^{2} x}{{ \cos}^{2} x}   +\frac{ \cos(x) }{\sin(x) ) }  \times  \frac{{ \sin}^{4} x}{{ \cos}^{4} x}

Cancel common factors:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  2 \frac{{ \sin}x}{{ \cos}x}   +\frac{{ \sin}^{3} x}{{ \cos}^{3} x}

This finally gives:

\cot(x)  \:  { \sec}^{4} x =  \cot(x) + 2 \tan(x)   +  { \tan}^{3} x

3 0
3 years ago
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