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3 years ago

Does anyone know how to answer these?? Need this before tomorrow

Mathematics

1 answer:

Rudik [331]3 years ago

7 0

This isnt an answer sorry but use photomath. ot works and you take a picture and it answers immediately.

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8j + 3-j=17 solve for J

givi [52]

First you have to combine like terms which you would combine 8j and j which would be 7j+3=17 then subtract 3 from 17 giving you 14. And after that your left with 7j=14 then divide 7 on both sides giving you 2 as your answer.

8 0

3 years ago

Read 2 more answers

PLEASE help me solve this question! No nonsense answers, and attach full solutions please!

Furkat [3]

Answer:

6.4 seconds

Step-by-step explanation:

Using the second equation of motion.

d= 200m/s.

a= 9.8ms^-1 . Acceleration due to gravity.

t= time.

substituting,

$\sqrt{2 \times \frac{200}{9.8} }$

t= 6.4 seconds

6 0

4 years ago

9. 1.3(c – 4) ≤ 2.6 + 0.7c

Julli [10]

Answer:

c ≤ 13

I think what was the question tho

Step-by-step explanation:

3 0

3 years ago

What is the length of BC? 5 12 A.7 B.12 C.13 D.17

sesenic [268]

Answer:

its A. 7

Step-by-step explanation:

5 0

3 years ago

"Find the point at which the line touches the circle" I really need help no one helped last time...

Troyanec [42]

The solution for a system of equations will be when the graphs touch each other, or intersect, and that happens when both equations equate each other, so, let's do so,

$\bf \begin{cases}
\boxed{y}=3x+10\\
-------\\
x^2+y^2=10\\
y^2=10-x^2\\
y=\sqrt{10-x^2}
\end{cases}\qquad \qquad \boxed{3x+10}=\sqrt{10-x^2}
\\\\\\
\textit{now we square both sides}\qquad (3x+10)^2=(\sqrt{10-x^2})^2
\\\\\\
(3x+10)^2=10-x^2\implies 9x^2+60x+100=10-x^2
\\\\\\
10x^2+60x-90=0\implies x^2+6x-9=0\implies (x+3)(x+3)=0
\\\\\\
x=
\begin{cases}
-3\\
-3
\end{cases}\qquad thus\qquad \boxed{x=-3}$

$\bf -------------------------------\\\\
\textit{now, when x = -3, what is \underline{y}?}\qquad y=3x+10\implies y=3(-3)+10
\\\\\\
y=-9+10\implies \boxed{y=1}\qquad \qquad therefore\qquad (\stackrel{x}{-3}~,~\stackrel{y}{1})$

6 0

3 years ago