With any equation you are allowed to take the logarithm of both sides so
5^c=125 now take the logarithm base 5 to both sides giving.
log5(5^c)=log5(125), using the rule log(a^b)=a*log(b) you get
c log5(5)=log5(125), since log5(5)=1
c=log5(125)
<span>A 2% solution of chlorohexidine added to 126 oz of water. The total oz 128.
Solute: chlorohexidine, 2%=0.02
solvent: water (0%)
Concentration, C, volume V
CV=c1v1+c2v1
128C=0.02*2 + 0.00*126 = 0.04
Concentration
C=0.04/128 = 0.0003125 = 0.03125%</span>
P² + 14p + 40
= p² + 10p + 4p + 40
= p(p+10) + 4(p+10)
= (p+10)(p+4)
B. (Not sure)
(5+A)
———
(a-1)
Answer:
ok
Step-by-step explanation:
