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mel-nik [20]
3 years ago
11

The table below represents an exponential function

Mathematics
1 answer:
Tom [10]3 years ago
3 0
The answer is The answer is A!
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A) 60° B) 85° C) 96° D) 40°​
RideAnS [48]

Answer:

A)60°

Step-by-step explanation:

a straight line is 180° then

if a line bisect it in to a half it become 90°

then

the exterior angle of a triangle is equal to the sum of two interior angles

this means 150°-90°=60°

8 0
3 years ago
Read 2 more answers
Please zoom in the picture for the question.
Mazyrski [523]
There’s a 2/6 chance that the science project would be first
3 0
2 years ago
Show that 3650 is not a perfect square.​
KatRina [158]

Answer:

A number that is a perfect square never ends in 2, 3, 7 or 8. If your number ends in any of those numbers, you can stop here because your number is not a perfect square. Obtain the digital root of the number. The digital root essentially is the sum of all of the digits.

Step-by-step explanation:

hope this helps you super sorry if it does not

4 0
2 years ago
Read 2 more answers
two mountain bikers leave from the same parking lot and head in opposite directions on two different trails. the first rider goe
sveta [45]

Applying the required <em>rule </em>or <em>theorem</em>, it can be concluded that the second biker is <u>farther</u> from the <em>parking lot</em>. The distance of the bikers to the <em>parking lot</em> are:

i. First biker = 17.0 km

ii. Second biker = 20.22 km

The <u>path</u> of travel of both bikers would form a triangle. Applying the <u>Pythagoras</u> theorem to the path of the <em>first</em> biker would give his <u>distance</u> from the starting point. While applying the <u>cosine</u> rule to the path of <em>second</em> rider would gives his <u>distance</u> to the starting point.

Thus,

a. <u>To determine the distance of the first biker from the parking lot.</u>

Let the required <em>distance </em>be represented by x. Applying the Pythagoras theorem, we have:

hyp^{2} = adj 1^{2} + adj 2^{2}

x^{2} = 8^{2} + 15^{2}

   = 64 + 225

   = 289

x = \sqrt{289}

  = 17

x = 17 km

Thus, the <u>first</u> biker is 17.0 km from the <em>starting</em> point.

b. <u>To determine the distance of the second biker from the parking lot.</u>

Let the required <em>distance</em> be represented by x. So that applying the cosine rule, we have:

c^{2} = a^{2} + b^{2} - 2ab Cos θ

x^{2} = 8^{2} + 15^{2} - 2(15*8) Cos (180 - 20)

    = 64 + 225 - 240 Cos 160

    = 289 - 240 * -0.5

x^{2} = 289 + 120

   = 409

x = \sqrt{409}

 = 20.2237

x = 20.22 km

Thus, the <u>second</u> biker is 20.22 km from the <em>starting</em> point.

Therefore, the second biker is <u>farther</u> from the <em>parking lot</em>.

A sketch of the path of travel for the two bikers is attached for more clarifications.

Visit: brainly.com/question/22699651

7 0
2 years ago
HELP PLEASE<br> Find the value of y. Round to<br> the nearest tenth.<br> у<br> 42°<br> 85°<br> 31
MaRussiya [10]
31
Explanation
Nothing
6 0
2 years ago
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