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KiRa [710]
2 years ago
12

14 80 tiles of side 30cm were used to cover a counter top. Calculate the area of the counter top in square metres.​

Mathematics
1 answer:
Komok [63]2 years ago
3 0

Answer:

Step-by-step explanation:

1,480 is a lot of tiles. Did you mean 80 tiles?

30 cm = 0.3 m

Area of one tile = 0.3² m² = 0.09 m²

Multiply the number of tiles by 0.09 m².

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It’s not B can someone plz help me with this it will be appreciated I’m really confused
Viktor [21]

Answer:

83.4

Step-by-step explanation:

Area of a Regular Polygon: L (of side) times apothem (height) x 1/2

L : 13.9

Looking at the triangle we can assume the height would be 12 since its logical that 3 of the 4 lines can fit in the middle of the triangle.

H: 12

13.9 x 12 = 166.8

166.8/2 = 83.4

3 0
3 years ago
PLEASE HELP TY OMG TYTYTY
Naya [18.7K]

Answer:

-14x

Step-by-step explanation:

To put in simple terms, this question is asking what -2x+-12x is. To solve this you must add -2 and -12. So... -2+-12=-14. Then add the one "x" at the end.

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3 years ago
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Ket [755]

Answer:

See explanation

Step-by-step explanation:

We want to show that:

\tan(x +  \frac{3\pi}{2} )  =  -   \cot \: x

One way is to use the basic double angle formula:

\frac{ \sin(x +  \frac{3\pi}{2} ) }{\cos(x +  \frac{3\pi}{2} )}  =  \frac{ \sin(x)  \cos( \frac{3\pi}{2} )  +   \cos(x)  \sin( \frac{3\pi}{2}) }{\cos(x)  \cos( \frac{3\pi}{2} )   -    \sin(x)  \sin( \frac{3\pi}{2}) }

\frac{ \sin(x +  \frac{3\pi}{2} ) }{\cos(x +  \frac{3\pi}{2} )}  =  \frac{ \sin(x) ( 0)  +   \cos(x) (  - 1) }{\cos(x) (0)   -    \sin(x) (  - 1) }

We simplify further to get:

\frac{ \sin(x +  \frac{3\pi}{2} ) }{\cos(x +  \frac{3\pi}{2} )}  =  \frac{ 0  -   \cos(x) }{0 +    \sin(x) }

We simplify again to get;

\frac{ \sin(x +  \frac{3\pi}{2} ) }{\cos(x +  \frac{3\pi}{2} )}  =  \frac{- \cos(x) }{ \sin(x) }

This finally gives:

\frac{ \sin(x +  \frac{3\pi}{2} ) }{\cos(x +  \frac{3\pi}{2} )}  =  -  \cot(x)

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