All categories

2 years ago

Julio is paid 1.1 times his normal hourly rate for each hour he works over 30 hours in a week. Last week he

Mathematics

1 answer:

Elena L [17]2 years ago

5 0

Answer:

Julio's hourly rate is $14.4 per hour

Step-by-step explanation:

Let

r ------> Julio's normal hourly rate

we know that

The linear equation that represent this scenario is

30r+(41-30)(1.1r)=606.24

30r+(11)(1.1r)=606.24

30r+12.1r=606.24

42.1r=606.24

Solve for r

r=606.24/42.1

r=14.4

therefore

Julio's hourly rate is $14.4 per hour

<em>Verify</em>

606.24=30(14.4)+(41-30)(1.1)(14.4)

606.24=432+174.24

606.24=606.24 ------> is ok

You might be interested in

Evaluate a + b for a= 34 and b= -6

SpyIntel [72]

Answer:

Hey there!

a+b

34+(-6)

34-6

Let me know if this helps :)

4 0

3 years ago

Muke is sick with the flu but he still cors to school on monday. He areives at 8am and by 9am (hour 1) muke has already infected

Volgvan

Answer:

$\begin{array}{ccccccccc}{Hours} & {0} & {1} & {2} & {3} & {4}& {5} & {6} & {7} \ \\ {Persons} & {1} & {2} & {4} & {8} & {16}& {32} & {64} & {128} \ \end{array}$

Step-by-step explanation:

Given

See attachment for complete question

Solving (a): Complete the table

Let

$x = hours$

$y = persons$

From the table question, we have:

$(x_1,y_1) = (0,1)$

$(x_2,y_2) = (1,2)$

$(x_3,y_3) = (2,4)$

The pattern follows that, an increment in x by doubles the value of 1.

So, the other values are:

$(x_4,y_4) = (3,8)$

$(x_5,y_5) = (4,16)$

$(x_6,y_6) = (5,32)$

$(x_7,y_7) = (6,64)$

$(x_8,y_8) = (7,128)$

So, the complete table is:

$\begin{array}{ccccccccc}{Hours} & {0} & {1} & {2} & {3} & {4}& {5} & {6} & {7} \ \\ {Persons} & {1} & {2} & {4} & {8} & {16}& {32} & {64} & {128} \ \end{array}$

Solving (b): The graph

The table follows an exponential function:

$y = ab^x$