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3 years ago

Julio is paid 1.1 times his normal hourly rate for each hour he works over 30 hours in a week. Last week he

Mathematics

1 answer:

Elena L [17]3 years ago

5 0

Answer:

Julio's hourly rate is $14.4 per hour

Step-by-step explanation:

Let

r ------> Julio's normal hourly rate

we know that

The linear equation that represent this scenario is

30r+(41-30)(1.1r)=606.24

30r+(11)(1.1r)=606.24

30r+12.1r=606.24

42.1r=606.24

Solve for r

r=606.24/42.1

r=14.4

therefore

Julio's hourly rate is $14.4 per hour

<em>Verify</em>

606.24=30(14.4)+(41-30)(1.1)(14.4)

606.24=432+174.24

606.24=606.24 ------> is ok

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Find AB when given angle B 64 degress angle C 75 degrese and side a 19

jeka94

Answer:

about 28

Step-by-step explanation:

you have to use the sine rule = side you know * ( sin of angle opposing the side you want to know / sin of angle opposing the side you know)

AB = 19* (sin 75/ sin ( 180 -75-64) )

AB = 19 * ( sin 75 / sin 41) ≈ 27.9739...

4 0

3 years ago

A sanitation department is interested in estimating the mean amount of garbage per bin for all bins in the city. In a random sam

soldi70 [24.7K]

Answer:

a) $52.8-2.02\frac{3.9}{\sqrt{40}}=51.554$

b) $52.8+2.02\frac{3.9}{\sqrt{40}}=54.046$

c) $52.8-2.71\frac{3.9}{\sqrt{40}}=51.129$

d) $52.8+2.71\frac{3.9}{\sqrt{40}}=54.471$

e) Yes, depends of the confidence level.

At 95 % of confidence the value 54.1985 pounds is not included on the interval. At 5% of significance the statement is FALSE.

At 99 % of confidence the value 54.1985 pounds is included on the interval. So at 1% of significance the statement is TRUE.

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X =52.8$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=3.9 represent the sample standard deviation

n=40 represent the sample size

a) What is the lower limit of the 95% interval? Give your answer to three decimal places

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=40-1=39$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,39)".And we see that $t_{\alpha/2}=2.02$

Now we have everything in order to replace into formula (1):

$52.8-2.02\frac{3.9}{\sqrt{40}}=51.554$

b) What is the upper limit of the 95% interval? Give your answer to three decimal places

$52.8+2.02\frac{3.9}{\sqrt{40}}=54.046$

So on this case the 95% confidence interval would be given by (51.554;54.046)

c) What is the lower limit of the 99% interval? Give your answer to three decimal places

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,39)".And we see that $t_{\alpha/2}=2.71$

Now we have everything in order to replace into formula (1):

$52.8-2.71\frac{3.9}{\sqrt{40}}=51.129$

d) What is the upper limit of the 99% interval? Give your answer to three decimal places

$52.8+2.71\frac{3.9}{\sqrt{40}}=54.471$

So on this case the 99% confidence interval would be given by (51.129;54.471)

e) Consider the claim that the mean amount of garbage per bin is 54.1985 pounds. Is the following statement true or false? The decision about the claim would depend on whether we use a 95% or 99% confidence interval: True/False

Yes, depends of the confidence level.

At 95 % of confidence the value 54.1985 pounds is not included on the interval. At 5% of significance the statement is FALSE.

At 99 % of confidence the value 54.1985 pounds is included on the interval. So at 1% of significance the statement is TRUE.

3 0

4 years ago

Solve for t.<br><br> 5t + 19 = 4t + 5

frosja888 [35]

Answer:

here ,

5t + 19= 4t +5

or ,5t-4t=5-19

or,t=-14

therefore T=-14

8 0

3 years ago

Read 2 more answers

A researcher wished to compare the effect of two stepping heights (low and high) on heart rate in a step-aerobics workout. A col

Alinara [238K]

Answer:

The answer is "between 0.10 and 0.05".

Step-by-step explanation:

For sample 1:

$n_1 = 25\\\\\bar{x_1} = 90.00\\\\ s_1 = 9\\\\$

For sample 2:

$n_2 = 25\\\\ \bar{x_2} = 95.08\\\\ S_2 = 12\\\\$

Calculating the null and alternative hypotheses:

$H_O : \mu_1 = \mu_2 \\\\ H_Q : \mu_1$

Calculating the test statistic:

$Z= \frac{90-95.08}{ \sqrt{\frac{9^2}{25}+\frac{12^2}{25}}} \\\\ =\frac{-5.08}{ \sqrt{\frac{81}{25}+\frac{144}{25}}}\\\\=\frac{-5.08}{ \sqrt{\frac{81+144}{25}}}\\\\=\frac{-5.08}{ \sqrt{\frac{225}{25}}}\\\\=\frac{-5.08}{ \frac{15}{5}}\\\\=\frac{-5.08}{3}\\\\= -1.693$