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2 years ago

How to solve a system of three equations using the elimination method

Mathematics

1 answer:

kolbaska11 [484]2 years ago

3 0

Answer:

1. Write all the equations in standard form, leaving out decimals or fractions.

2. Select the variables to be eliminated; And then you take two of these equations, and you eliminate the variables.

3. Select a different set of two equations and eliminate the same variables as in step 2.

4. Solve two equations containing two variables from steps 2 and 3.

5. Substitute the answer to step 4 into any equation that contains the remaining variables.

6. Check the solution with three original equations.

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A car valued at £15000

lara31 [8.8K]

The answer u can take 15000x5=75.000

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2 years ago

6. a. Sixty students in a class took an examination in Physics and Mathematics. If 17 of them passed Physics only, 25 passed in

Ivahew [28]

Let $C$ be the set of all students in the classroom.

Let $P$ and $M$ be the sets of students that pass physics and math, respectively.

We're given

$n(C) = 60$

$n(P \cap M') = 17$

$n(P \cap M) = 25$

$n((P \cup M)') = n(P' \cap M') = 9$

i. We can split up $P$ into subsets of students that pass both physics and math $(P\cap M)$ and those that pass only physics $(P\cap M')$ . These sets are disjoint, so

$n(P) = n(P\cap M) + n(P\cap M') = 25 + 17 = \boxed{42}$

ii. 9 students fails both subjects, so we find

$n(C) = n(P\cup M) + n(P\cup M)' \implies n(P\cup M) = 60 - 9 = 51$

By the inclusion/exclusion principle,

$n(P\cup M) = n(P) + n(M) - n(P\cap M)$

Using the result from part (i), we have

$n(M) = 51 - 42 + 25 = 34$

and so the probability of selecting a student from this set is

$\mathrm{Pr}(M) = \dfrac{34}{60} = \boxed{\dfrac{17}{30}}$

7 0

1 year ago

Cas walks 3/5 miles in 24 min at a steady pace, how long does it take him to walk 2 miles?

san4es73 [151]

Your answer is 80 mins, or an hour and 20 mins. You simply turn that fraction to a decimal by diving 3 with 5. This should turn out to be 0.6. Then you multiply the 24 mins with the 2 miles and it turns out to be 48. After this, you divide 48 by 0.6 and you get 80.

3 0

2 years ago

A cube with edges that measure 10 centimeters has a volume that is twice as much as a cube with sides that measure 5 centimeters

rodikova [14]

Answer:

False

Step-by-step explanation:

We find the volumes of the two cubes and compare them.

volume of cube = side^3

The volume of the 10-cm cube is:

V = (10 cm)^3 = 1000 cm^3

The volume of the 5-cm cube is:

V = (5 cm)^3 = 125 cm^3

1000/125 = 8

The volume of the 10-cm cube is 8 times the volume of the 5-cm cube.

The statement is false.

7 0

2 years ago

Which two transformations are applied to pentagon ABCDE to create A'B'C'D'E'?

vekshin1

The answer is C. I need a total of 20 characters so heres a smiley face:)

6 0

3 years ago