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3 years ago

How to solve a system of three equations using the elimination method

Mathematics

1 answer:

kolbaska11 [484]3 years ago

3 0

Answer:

1. Write all the equations in standard form, leaving out decimals or fractions.

2. Select the variables to be eliminated; And then you take two of these equations, and you eliminate the variables.

3. Select a different set of two equations and eliminate the same variables as in step 2.

4. Solve two equations containing two variables from steps 2 and 3.

5. Substitute the answer to step 4 into any equation that contains the remaining variables.

6. Check the solution with three original equations.

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3 years ago

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Step-by-step explanation:

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What is the center of the circle that you can circumscribe about a triangle with vertices A(2, 6), B(2, 0), and C(10, 0)?

denis23 [38]

The three points A,B,C are all points on this circle.
Each point is then equal distance from the center, that distance being the radius of the circle.
Using the distance formula, we can find the center of the circle (x,y):
$d^2 = (x-x_0)^2 + (y-y_0)^2$
Plugging in points A and B into distance formula, then setting them equal to each other gives:
$(x-2)^2+(y-6)^2 = (x-2)^2 + y^2$
Right away we can cancel out the x terms leaving:
$(y-6)^2 = y^2$
Expand Left side and Solve for y:
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$y = 3$
Plug in points B and C as before:
$(x-2)^2 + y^2 = (x-10)^2 + y^2$
Here we can cancel the y-terms.
Expand and solve for x:
$x^2 -4x+4 = x^2 -20x+100$
$16x = 96$
$x = 6$
Therefore the center of the circle is the point (6,3)

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3 years ago