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tankabanditka [31]
2 years ago
5

Solve for x. Help me out because I haven’t been paying attention all year

Mathematics
1 answer:
svet-max [94.6K]2 years ago
8 0

Answer:

x = 18

Step-by-step explanation:

(whole secant) x (external part) =  (whole secant) x (external part)

(6+x)6 = (8+10)* 8

6*(6+x) = 8(18)

Divide each side by 6

6+x = 8(18)/6

6+x = 8*3

6+x = 24

Subtract 6 from each side

6+x-6 =24-6

x = 18

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in a school the ratio of boys to girls 6/5. what is the probability of choosing a girl from a class of 22?
kifflom [539]

the ratio 6/5 means for every 6 boys there are 5 girls.

Add the ratio: 6+5 = 11

Divide class total by 11: 22/11 = 2

Multiply each ratio number by 2 to find the number of boys and the number of girls:

6 x 2 = 12 boys

5 x 2 = 10 girls.


10 out of the 22 kids are girls.


The probability of picking a girl would be 10/22, which reduces to 5/11

8 0
3 years ago
Nate has $50 to spend at the grocery store. He fills his shopping cart with items totaling $46. At checkout he will have to pay
Deffense [45]

Answer:

yes

Step-by-step explanation:

Find the amount of the sales tax:

46 x 0.06 = 2.76

Add the sales tax to the items total:

46 + 2.76 = 48.76

50 > 48.76

Since $48.76 is less than $50 he has enough money

5 0
3 years ago
Find a report in a newspaper or magazine or in the internet that uses results from a survey
Radda [10]
I think you might need to be more specific..
8 0
2 years ago
For any circle, which ratio is equal to the number n? Select all that apply. Plsss help me!!
barxatty [35]

Answer:

Options A-C-F

Step-by-step explanation:

we know that

<em>The circumference of a circle is equal to</em>

C=\pi D  or  C=2\pi r

where

D is the diameter and r is the radius

therefore

\pi =\frac{C}{D}  or \pi =\frac{C}{2r}

The number pi is the ratio circumference - diameter or is the ratio circumference - 2 times radius

<em>The area of the circle is equal to</em>

A=\pi r^{2}

therefore

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6 0
3 years ago
Answer this pls..................​
Sindrei [870]

Answer:

so we know:

total of 20 students

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

chemistry has a total of 14 students

1 2 3 4 5 6 7 8 9 10 11 12 13 14

8 students are in physics

1 2 3 4 5 6 7 8

3 are in all of them

1 2 3

1) underline the main 3

total of 20 students

<u>1 2 3 </u>4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

chemistry has a total of 14 students

<u>1 2 3</u> 4 5 6 7 8 9 10 11 12 13 14

8 students are in physics

<u>1 2 3 </u>4 5 6 7 8

2) lets bold the physics students, if you are in physics you have to do chem so that means 8 of the chem students also take physics.

total

<u>1 2 3 </u>4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

chemistry

<u>1 2 3</u> 4 5 6 7 8 9 10 11 12 13 14

physics

<u>1 2 3 </u>4 5 6 7 8

3) now we bring biology into the "equation"

off the bat we know 3 are definitely in Biology.

so if 4 study ONLY biology we can cross them off our list see the {}

total

<u>1 2 3 </u>4 5 6 7 8 {9 10 11 12} 13 14 15 16 17 18 19 20

chemistry

<u>1 2 3</u> 4 5 6 7 8 {9 10 11 12} 13 14

physics

<u>1 2 3 </u>4 5 6 7 8

biology

<u>1 2 3 </u>

<u />

4) so we have a total of 20 students, 3 in all of the classes <u>(underlined)</u>, 8 in physics (bolded). If there 14 in chemistry, 4 take ONLY chemistry {}, 8 take chemistry as well (bolded), that leaves two students, so they must belong in biology. lets<em> italicise</em> them.

total

<em><u>1 2 3 </u></em>4 5 6 7 8 {9 10 11 12} <em>13 14</em> 15 16 17 18 19 20

chemistry

<em><u>1 2 3</u></em><em> </em>4 5 6 7 8 {9 10 11 12} <em>13 14</em>

physics

<em><u>1 2 3</u></em><u> </u>4 5 6 7 8

biology

<em><u>1 2 3 </u></em><em> 13 14</em>

<u />

5) out of our total of 20 students we know 14 of the students classes, so the remaining six must be in biology.

<u>1 2 3 </u>4 5 6 7 8 {9 10 11 12} <em>13 14</em> 15 <em>16 17 18 19 20</em>

chemistry

<u>1 2 3</u> 4 5 6 7 8 {9 10 11 12} <em>13 14</em>

physics

<u>1 2 3 </u>4 5 6 7 8

biology

<u>1 2 3 </u><em>13 14</em> 15 <em>16 17 18 19 20</em>

6) so that was our "diagram" so now lets count how many are in chemistry and biology but NOT physics.

<u>1 2 3 </u>4 5 6 7 8 {9 10 11 12} <em>13 14</em> 15 <em>16 17 18 19 20</em>

chemistry

<u>-1 2 3</u> 4 5 6 7 8- {9 10 11 12} <em>13 14</em>

physics

<u>-1 2 3 </u>4 5 6 7 8-

biology

<u>-1 2 3 -</u><em>13 14</em> 15 <em>16 17 18 19 20</em>

there are 14 students in chemistry and 11 in biology, 5 of them are in both classes so 14-5= 9 and 11-5= 6 9+6=16. BUT 8 of those sixteen are also in -physics- so we arent counting them, we put those students in dashes. so lets count the students out of the dashes. so<em> twelve</em> of them are in chemistry and biology but not physics.

7) so how many are in just biology but not the other classes? lets look at the graph.

<u>1 2 3 </u>4 5 6 7 8 {9 10 11 12} <em>13 14</em> 15 <em>16 17 18 19 20</em>

chemistry

<u>1 2 3</u> 4 5 6 7 8 {9 10 11 12} <em>13 14</em>

physics

<u>1 2 3 </u>4 5 6 7 8

biology

<u>1 2 3 </u><em>13 14</em> 15 <em>16 17 18 19 20</em>

in the class of biology students 1 2 3 13 and 14 take other classes that leaves students 15 16 17 18 19 and 20. so 6 students take ONLY biology.

sorry its long but i hope this helps!

3 0
2 years ago
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