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Lady_Fox [76]
3 years ago
14

Line m passes through points P(–1, 5) and Q(2, 3) on an xy-coordinate plane. Write an equation for the line that is perpendicula

r to line m at point P.
Mathematics
1 answer:
kap26 [50]3 years ago
7 0
Y = 3x + 2 glad i could help u
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What expression is equivalent to 12 - 1/2(x + 12)
lyudmila [28]
Distribute the -1/2 to both x and 12

-1/2(x) = -1/2x
-1/2(12) = -6

12 -  (-1/2x) - 6

Simplify: Note, two negatives = one positive

12 + 1/2x - 6

Simplify: combine common numbers together

12 - 6 + 1/2x

6 + 1/2x


1/2x + 6 is your equivalent expression


hope this helps
7 0
3 years ago
Thomas paid a one-time registration
Mkey [24]

Answer:

There is no error

Step-by-step explanation:

He stated with 15 15x and made 10 for each y=15+10

3 0
3 years ago
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B) Find the value of a^2 + b^2 when a = 3 and b= -2
Zielflug [23.3K]

Answer:

13

Step-by-step explanation:

a = 3

b = -2

a² + b² = 3² + (-2)²

= 9 + 4

= 13

5 0
3 years ago
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Use a truth table to verify the first De Morgan law (p ∧ q)’ ≡ p’ ∨ q’.
Nutka1998 [239]

Answer:

(p ∧ q)’ ≡ p’ ∨ q’

Step-by-step explanation:

First, p and q have just four (4) possibilities, p∧q is true (t) when p and q are both t.

p ∧    q

t t t

t f f

f f t

f f f

next step is getting the opposite

(p∧q)'

    <em>f</em>

<em>     t</em>

<em>     t</em>

<em>     t</em>

Then we get p' V q', V is true (t) when the first or the second is true.

p' V  q'

f  <em>f</em>  f

f  <em>t</em>  t

t  <em>t</em>  f

t  <em>t</em>  t

Let's compare them, ≡ is true if the first is equal to the second one.

(p∧q)'   ≡     (p' V q')

    <em>f              f </em>

<em>     t              t</em>

<em>     t              t</em>

<em>     t              t</em>

Both are true, so

(p ∧ q)’ ≡ p’ ∨ q’

6 0
3 years ago
Find equivalent ways to rewrite the expression 6a^8÷3a^4​
solong [7]

Answer:

6a^8/3a^4= (6/3)= 2

a^8/a^4= a^4

2a^4

(6/3)(a^8/a^4)= 2a^4

(6/3)(a^(8-4))= 2a^4

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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