So you would use the law of sines so set up the equation sin18/16 = sin72/x (sin 72 being the top angle) and then you cross multiply and solve from there:)
Hope this helps!
You haven't provided neither the diagram nor the options.
Therefore, I cannot provide an exact answer, however, I will try to help you with the concept.
<u>For a triangle, the measure of each angle is proportional to the length of its opposite side.</u>
<u>This means that:</u>
1- The largest angle is the angle opposite to the longest side
2- The smallest angle is the angle opposite to the shortest side
Since you are looking for the largest angle, pick the one facing the longest side
<u>Some tips and tricks:</u>
<u>1- In a right angle triangle</u>, we know that the hypotenuse is the longest side, therefore, the largest angle would be the right angle
<u>2- In an obtuse triangle</u>, the largest angle is simply the obtuse angle itself (the one whose measure is greater than 90)
<u>3- In equilateral triangle</u>, all three angles are equal
Hope this helps :)
h(r+1)
q could be 6 and it can be substituted with h
First step is to analyze input and output variables:
INPUT:
list of integers with name "values"
integer with name "p1"
integer with name "p2"
OUTPUT:
there is no output variable as in declaration of a method there is void
ANALYSIS:
"<span>int temp = values[p1]"
this line creates variable "temp" which is integer. then this line goes to the list "values" and takes value that is at position "p1" and stores it into variable "temp"
"</span><span>values[p1] = values[p2]"
this line </span>goes to the list "values" and takes value that is at position "p2" and stores it into variable that is at position "p1"
"<span>values[p2] = temp"
this line takes value of the variable "temp" and stores it into list values at position "p2"
Short explanation:
this code replaces values of the list at between positions p1 and p2</span>
Answer:
Hello yellow I'm angalena hoflin
