Three cards are drawn with replacement from a standard deck. What is the probability that the first card will be a diamond, the
1 answer:
Answer:
The probability that the first card will be a diamond, the second card will be a black card, and the third card will be a queen is 0.0096
Step-by-step explanation:
Total no. of cards = 52
No. of diamond cards = 13
No. of black cards = 26
No. of queens = 4
Three cards are drawn with replacement from a standard deck.
We are supposed to find he probability that the first card will be a diamond, the second card will be a black card, and the third card will be a queen
Probability of getting diamond card =
Probability of getting black card =
Probability of queen =
Probability that the first card will be a diamond, the second card will be a black card, and the third card will be a queen =
Hence the probability that the first card will be a diamond, the second card will be a black card, and the third card will be a queen is 0.0096
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Answer:
a) There is a 10.75% probability of observing less than 60 hits in an hour.
b) The 99th percentile of the distribution of the number of hits is 95.21 hits.
c) There is a 24% probability of observing between 80 and 90 hits an hour
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by
After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.
In this problem, we have that
The web logs of a certain website show that the average number of hits in an hour is 75 with a standard deviation equal to 8.6, so .
a) What’s the probability of observing less than 60 hits in an hour? Use the normal approximation
This is the pvalue of Z when X = 60. So
has a pvalue of 0.1075. This means that there is a 10.75% probability of observing less than 60 hits in an hour.
b) What’s the 99th percentile of the distribution of the number of hits?
What is the value of X when Z has a pvalue of 0.99.
Z = 2.35 has a pvalue of 0.99
So
The 99th percentile of the distribution of the number of hits is 95.21 hits.
c) What’s the probability of observing between 80 and 90 hits an hour?
This is the pvalue of the zscore of X = 90 subtracted by the pvalue of the zscore of X = 80.
For X = 90
has a pvalue of 0.95907
For X = 80
has a pvalue of 0.71904
So
There is a 0.95907 - 0.71904 = 0.24003 = 24% probability of observing between 80 and 90 hits an hour