Answer: 5
Step-by-step explanation:
5x7=35
35-4=31
Mean = $52
median = $53
no mode
range = 63 - 40 = $23
Answer:
- P(t) = 100·2.3^t
- 529 after 2 hours
- 441 per hour, rate of growth at 2 hours
- 5.5 hours to reach 10,000
Step-by-step explanation:
It often works well to write an exponential expression as ...
value = (initial value)×(growth factor)^(t/(growth period))
(a) Here, the growth factor for the bacteria is given as 230/100 = 2.3 in a period of 1 hour. The initial number is 100, so we can write the pupulation function as ...
P(t) = 100·2.3^t
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(b) P(2) = 100·2.3^2 = 529 . . . number after 2 hours
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(c) P'(t) = ln(2.3)P(t) ≈ 83.2909·2.3^t
P'(2) = 83.2909·2.3^2 ≈ 441 . . . bacteria per hour
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(d) We want to find t such that ...
P(t) = 10000
100·2.3^t = 10000 . . . substitute for P(t)
2.3^t = 100 . . . . . . . . divide by 100
t·log(2.3) = log(100)
t = 2/log(2.3) ≈ 5.5 . . . hours until the population reaches 10,000
Answer:
D
Step-by-step explanation:
Converting percent to decimal : 2.2/100 = 0.022
Finding 2.2$ of $75k : 75,000 x 0.022 = $1,650 (also the increase in one year)
Finding how much it was worth after 11 years :
(75,000 x 0.022) x 11 = $18,150 or 1,650 x 11 = $18,150
Now add the product to the regular amount to find out the answer:
75,000 + 18,150 = $93,150 (which is how much it increased after 11 years)