1. The midpoint of the segment joining points (a, b) and ( j, k) is ((j+a)/2,(k+b)/2)
2. Let the coordinate of H be (a, b)
T(0, 4) = ((a + 0)/2, (b + 2)/2)
(a + 0)/2 = 0 => a + 0 = 0 => a = 0
(b + 2)/2 = 4 => b + 2 = (2 x 4) = 8 => b = 8 - 2 = 6
Therefore, the cordinate of H is (0, 6)
3. Point (-4, 3) lies in Quadrant II
4. Point (6, 0) lies on the x-axis
5. Any line with no slope is parallel to the y-axis
7. a is the value of the x-coordinate.
5a + 3 = 8
5a = 8 - 3 = 5
a = 5/5 = 1
a = 1
8. Equation of a circle is given by (x - a)^2 + (y - b)^2 = r^2; where (a, b) is the center and r is the radius.
For the given circle (x + 5)^2 + (y - 7)^2 = 36 => (x - (-5))^2 + (y - 7)^2 = 6^2 => a = -5 and b = 7.
Therefore, its center point is (-5, 7)
9. Equation of a circle is given by (x - a)^2 + (y - b)^2 = r^2; where (a, b) is the center and r is the radius.
For the given circle (x + 5)^2 + (y - 7)^2 = 36 => (x - (-5))^2 + (y - 7)^2 = 6^2 => r = 6.
Therefore, its radius is 6
10. If the equation of a circle is (x - 2)^2 + (y - 6)^2 = 4, the center is point (2, 6).
True
Answer:
Answer: 1/81
First you simplify it to 3^-4
Then express it with a positive exponent
which goes to 1/3^4
Then evaluate it to 1/81
Answer:
No solutions
Step-by-step explanation:
In this question, you would be solving for x.
Solve:
5 + 2(3 + 2x) = x + 3(x + 1)
Use the distributive property.
5 + 6 + 4x = x + 3x + 3
Combine like terms.
11 + 4x = 4x + 3
Subtract 4x from both sides.
11 = 3
Since we don't have an "x value", there are no solutions.
"No solutions" would be your answer.
7/10n + 14 = 49
7/10n = 35
n = 35 x 10/7
n = 50
In 1, t<span>here are 6 outcomes for each die, so for three dice, the total combination is 6 x 6 x 6 = 216 outcomes. Hence, t</span><span>he probability of any individual outcome is 1/216 </span>
The outcomes that will add up to 6 are
<span>1+1+4 </span>
<span>1+4+1 </span>
<span>4+1+1 </span>
<span>1+2+3 </span>
<span>1+3+2 </span>
<span>2+1+3 </span>
<span>2+3+1 </span>
<span>3+1+2 </span>
<span>3+2+1 </span>
<span>2+2+2 </span>
<span>Hence the probability is </span><span>10/216 </span>
In 3, the minimum sum of the three dice is 3. so we start with this
<span>P(n = 3) </span>
<span>1+1+1 ; </span><span>1/216 </span>
<span>P(n = 4) </span>
<span>1+1+2 </span>
<span>1+2+1 </span>
<span>2+1+1 ; </span><span>3/216 </span>
<span>P(n = 5) </span>
<span>1+1+3 </span>
<span>1+3+1 </span>
<span>3+1+1 </span>
<span>1+2+2 </span>
<span>2+1+2 </span>
<span>2+2+1; </span><span>6/216
The sum in 3 is 10/216 or 5/108</span>
