Step-by-step explanation:
Draw diagonal AC
The triangle ABC has sides 17 and 25
Say AB is 17, BC is 25
Draw altitude on side BC from A , say h
h = 17 sin B
Area = 25*17 sin B = 408
sin B = 24/25
In ∆ ABC
Cos B = +- 7/25
= 625 + 289 — b^2 / 2*25*17
b^2 = 914 — 14*17 = 676
b = 26
h = 17*24/25 = 408/25 = 16.32
Draw the second diagonal BD
In ∆ BCD, draw altitude from D, say DE =h
BD^2 = h^2 + {(25 + sqrt (289 -h^2) }^2
BD^2 = 16.32^2 + (25 + 4.76)^2
= 885.6576 + 266.3424
BD = √ 1152 = 33.94 m
this is the answer y=−1/2x+45/2
$95.00 minus $9.50 equals $85.50
Answer:
97.3%
Step-by-step explanation:
Let the three bulbs be A, B and C respectively.
Let P(A) denote the probability that the first bulb will burn out
Let P(B) denote the probability that the second bulb will burn out
Let P(C) denote the probability that the third bulb will burn out
Now, we are told that Each one has a 30% probability of burning out within the month.
Thus;
P(A) = P(B) = P(C) = 30% = 0.3
Now, probability that at the end of the month at least one of the bulbs will be lit will be given as;
P(at least one bulb will be lit) = 1 - (P(A) × P(B) × P(C))
P(at least one bulb will be lit) = 1 - (0.3 × 0.3 × 0.3) = 0.973 = 97.3%
Answer:
-4
Step-by-step explanation:
16-20 = -4
