Answer:
At least one of the integer must be equal to zero to obtain the product zero
Step-by-step explanation:
we know that
When multiplying integers
, if one or both of the integers is 0, then the product is 0.
The multiplication property states that the product of any number and zero is zero.
so
a*(0)=0
therefore
At least one of the integer must be equal to zero to obtain the product zero
therefore
In order to solve this we'll start by assigning variables to hamburgers and cheeseburgers, since these are what we're trying to find. Lets say x = hamburgers and y = cheeseburgers. So we know two things, we know that x+y= 763 (hamburgers plus cheeseburgers sold equals 763, and we know that y= x+63 (cheeseburgers sold equals 63 more than hamburgers sold). Now we have a system of equations. This can be solved most easily by rearranging each equation to each y, and then set them equal to each other:
x+y=763 -> y=763-x, and we already have y=x+63. Set them equal to each other:
x+63 = 763-x (add x to both sides) -> 2x+63 = 763 (subtract 63 from both sides) -> 2x = 700 (divide both sides by 2) x = 350. So we solved for x, which is hamburgers sold, which is what the question asks for, so your answer is 350 hamburgers were sold on Saturday
Answer:
x=20
Step-by-step explanation:
Well just cross multiply if its easier
x(3)=3x
12*5=60
60=3x
x=20
Answers: 11,664
Explanation: idk I used Photomath
