Step-by-step explanation:
An=A1+(n-1)d
A30=10+(30-1)3
A30=10+(29)3
A30= 10+87
A30=97
it takes me a centuary to type
Answer:
see explanation
Step-by-step explanation:
given the 2 equations
y = x² - 2x - 19 → (1)
y + 4x = 5 → (2)
substitute y = x² - 2x - 19 into (2)
x² - 2x - 19 + 4x = 5 ( subtract 5 from both sides )
x² + 2x - 24 = 0 ← in standard form
(x + 6)(x - 4) = 0 ← in factored form
equate each factor to zero and solve for x
x + 6 = 0 ⇒ x = - 6
x - 4 = 0 ⇒ x = 4
substitute each value of x into (1) for corresponding y- coordinate
x = - 6 : y = (- 6)² - 2(- 6) - 19 = 36 + 12 - 19 = 29 ⇒ (- 6, 29)
x = 4 : y = 4² - 2(4) - 19 = 16 - 8 - 19 = - 11 ⇒ (4, - 11)
the solutions are (- 6, 29), (4, - 11)
The smallest possible value is 2625
Answer: Ali would need to drive 350 miles for the two plans to cost the same.
Step-by-step explanation:
This question can be solved by creating two equations using the information supplied in the question and then solving these simultaneously.
Let the cost be C.
Let the number of miles be M.
Let the initial payment be i.
Let the rate per mile driven be R.
Plan 1:
C = i+R×M
C = 70+0.60M ... equation 1
Plan 2:
C = i+R×M
C = 0+0.80M
C = 0.80M ...equation 2
Substituting equation 2 into equation 1:
0.80M = 70+0.60M
0.80-0.60M = 70
0.20M = 70
M = 70/0.20
M = 350 miles
I would personally take the number three and trow it out the window but that's not what we are talking about
