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vagabundo [1.1K]
3 years ago
8

Plz help(Give me the coordinates Im stuck)

Mathematics
1 answer:
dexar [7]3 years ago
7 0

Answer:

(-2, 3) is going to be your answer.

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3(2+7) - 9 x 7 = 3+8 x 2 x 2 - 4 = 16 ÷ 2 x 5 x 3 ÷ 6 = Please answer! ✨✨
Thepotemich [5.8K]

Answer:

At first, we have 3 expressions that are equal.

3(2+7) - 9 \cdot 7= 3+8 \cdot 2 \cdot 2 - 4

6+21 - 63= 3+32 - 4

-36=31

-36\neq 31

This is not true.

3 0
3 years ago
Plz help! It’s due soon!
gregori [183]
X-int: none
Y-int: (0,27)
Vertex: (-3,18)
AOS: x= -3
Max & Min Value: (-3,18)
8 0
3 years ago
Solve the equation 3p (3p - 8) - 8 = 9p ( p - 3 + 4
pentagon [3]

Answer:

p= \frac{-8}{33}

Explanation:

Given:

3p (3p - 8) - 8 = 9p ( p - 3 + 4)

To Find:

Value of p=?

Solution:

Before solving this equation,  we will use the method of BODMAS which states that we first solve the Bracket then Off then Division then Multiplier then addition and at last subtraction.  

Now we will solve the both right and left hand side of the equation  

3p (3p - 8) - 8 = 9p ( p - 3 + 4)

9p^2-24p-8=9p^2+9p

Gruoping the like terms we get,

9p^2-9p^2-24p-9p=8

After solving the both right hand and left hand side of the equation  

-33p=8

And we get the value of p as  

p= \frac{-8}{33}

4 0
3 years ago
Read 2 more answers
Mariah is debating whether to use a straightedge and compass or a computer drawing program to complete a construction of a regul
marshall27 [118]
I think the best way is to use a computer drawing program in constructing a regular hexagon inscribed in a circle. Its because a computer program is an accurate, precise and the most important it is more efficient than using the straight edge and compass
7 0
3 years ago
Read 2 more answers
Select the point that is a solution to the system of inequalities
Zarrin [17]
<h2>Hello!</h2>

The answer is:

The point that is a solution to the system of inequalities is C(4,2).

<h2>Why?</h2>

To find the point that is a solution to the system of inequalities, we need to evaluate it into the given inequalities. If the point is a solution to the system of inequalities, both inequalities will be satisfied.

We are given the inequalities:

y\leq 2x-2

y\leq x^{2} -3x

So, substituting the given points into the given inequalities, we have:

- A. (2,1)

Substituting into the first inequality, we have:

y\leq 2x-2\\\\1\leq 2*(2)-2\\\\1\leq 4-2\\\\1\leq 2

Substituting into the second inequality, we have:

y\leq x^{2} -3x

1\leq (2)^{2} -3(2)

1\leq (2)^{2} -3(2)

1\leq 4 -6

1\leq -2

Therefore, since 1 is not less or equal to -2, the point A(2,1) is not a solution to the system of inequalities.

- B. (-2,-1)

Substituting into the first inequality, we have:

y\leq 2x-2\\\\-1\leq (-2)*(2)-2\\\\-1\leq -4-2\\\\-1\leq -6

Substituting into the second inequality, we have:

y\leq x^{2} -3x

-1\leq (-2)^{2} -3(-2)

-1\leq 4 +6

-1\leq 10

Therefore, since -1 is not less or equal to -6, the point B(-2,-1) is not a solution to the system of inequalities.

- C. (4,2)

Substituting into the first inequality, we have:

y\leq 2x-2\\\\2\leq (4)*(2)-2\\\\2\leq 8-2\\\\2\leq 6

Substituting into the second inequality, we have:

y\leq x^{2} -3x

2\leq (4)^{2} -3(4)

2\leq 16 -12

2\leq 4

Therefore, since 2 is less than 6, and 2 is less than 4, the point B(4,2) is a solution to the system of inequalities.

- D(1,3)

Substituting into the first inequality, we have:

y\leq 2x-2\\\\3\leq (1)*(2)-2\\\\3\leq 2-2\\\\3\leq 0

Substituting into the second inequality, we have:

y\leq x^{2} -3x

3\leq (1)^{2} -3(1)

3\leq 1 -3

3\leq -2

Therefore, since 3 is not less than 0, and 3 is not less than -2, the point D(1.3) is not a solution to the system of inequalities.

Hence, the point that is a solution to the system of inequalities is C(4,2).

Have a nice day!

6 0
3 years ago
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