-5+3=-2-3+3=-2
Hope this helps
Hello,
Answer D
y=2x/7+4
x=2y/7+4
(x-4)*7/2=y
Answer:
Step-by-step explanation:
From the given information, we can compute the table showing the summarized statistics of the two alloys A & B:
Alloy A Alloy B
Sample mean 
Equal standard deviation 
Sample size 
Mean of the sampling distribution is :
Standard deviation of sampling distribution:
Hypothesis testing.
Null hypothesis: 
Alternative hypothesis: 
The required probability is:
![P(\overline X_A - \overline X_B>4|\mu_A - \mu_B) = P\Big (\dfrac{(\overline X_A - \overline X_B)-\mu_{X_A-X_B}}{\sigma_{\overline x_A -\overline x_B}} > \dfrac{4 - \mu_{X_A-\overline X_B}}{\sigma _{\overline x_A - \overline X_B}} \Big) \\ \\ = P \Big( z > \dfrac{4-0}{1.2909}\Big) \\ \\ = P(z \ge 3.10)\\ \\ = 1 - P(z < 3.10) \\ \\ \text{Using EXCEL Function:} \\ \\ = 1 - [NORMDIST(3.10)] \\ \\ = 1- 0.999032 \\ \\ 0.000968 \\ \\ \simeq 0.0010](https://tex.z-dn.net/?f=P%28%5Coverline%20X_A%20-%20%5Coverline%20X_B%3E4%7C%5Cmu_A%20-%20%5Cmu_B%29%20%3D%20P%5CBig%20%28%5Cdfrac%7B%28%5Coverline%20X_A%20-%20%5Coverline%20X_B%29-%5Cmu_%7BX_A-X_B%7D%7D%7B%5Csigma_%7B%5Coverline%20x_A%20-%5Coverline%20x_B%7D%7D%20%3E%20%5Cdfrac%7B4%20-%20%5Cmu_%7BX_A-%5Coverline%20X_B%7D%7D%7B%5Csigma%20_%7B%5Coverline%20x_A%20-%20%5Coverline%20X_B%7D%7D%20%20%20%5CBig%29%20%5C%5C%20%5C%5C%20%3D%20P%20%5CBig%28%20z%20%3E%20%5Cdfrac%7B4-0%7D%7B1.2909%7D%5CBig%29%20%5C%5C%20%5C%5C%20%3D%20P%28z%20%5Cge%203.10%29%5C%5C%20%5C%5C%20%3D%201%20-%20P%28z%20%3C%203.10%29%20%5C%5C%20%5C%5C%20%5Ctext%7BUsing%20EXCEL%20Function%3A%7D%20%5C%5C%20%5C%5C%20%20%3D%201%20-%20%5BNORMDIST%283.10%29%5D%20%20%5C%5C%20%5C%5C%20%3D%201-%200.999032%20%5C%5C%20%5C%5C%200.000968%20%5C%5C%20%5C%5C%20%5Csimeq%20%200.0010)
This implies that a minimal chance of probability shows that the difference of 4 is not likely, provided that the two population means are the same.
b)
Since the P-value is very small which is lower than any level of significance.
Then, we reject 
and conclude that there is enough evidence to fully support alloy A.
<h3>
Answer: Choice B</h3>
Reason:
Choices A, C and D have repeated x values. It allows us to rule them out.
Table A has x = 6 repeating. Table C has x = 3 and x = -3 repeated. Table D has x = 4 and x = 5 show up twice each.
Whenever we have repeated x values, it indicates we do <u>not</u> have a function. A function is only possible when each x value goes to exactly one y value only.
Table A has the input x = 6 lead to y = 2 and y = -2 at the same time. Table C and table D are a similar story. So this is another way to rule out choices A, C and D.
Luckily table B has no repeated x values. Each x input leads to exactly one and only one y output. Therefore, <u>table B</u> is a function.
Side Note: the y values can repeat, but the function won't be one-to-one.
Answer:
You can buy 3 items for $6, how
much will it cost for 10 items?
60$
Step-by-step explanation:
