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2 years ago

Solve each of the following equations using a method other than the Quadratic Formula.

Mathematics

1 answer:

liraira [26]2 years ago

8 0

Answer:

y^2-6y = 0

or, y(y-6) = 0

or, y = 0 or y = 6

n^2+5n+7 = 7

or, n^2+5n+7-7 = 7-7 ( Subtracting 7 from both sides)

or, n^2+5n = 0

or, n(n+5) = 0

or, n=0 or n= -5

2t^2-14t+3 = 3

or, 2t^2-14t = 0

or, 2t(t-7) = 0

or, t=0 or t=7

1/3x^2+3x-4 = -4

or, 1/3x^2+3x = 0

or, 1/3x(x+9) = 0

or, x=0 or x= -9

Zero is a common solution to each of the equations. This is because each of the equations had a variable outside the parenthesis with an operation of multiplication.

THANK YOU FOR READING.

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Your dad is designing a new garden for your backyard. He has 20 feet of fencing to go around the garden. He wants the length of

Komok [63]

Answer:

Length = 6.25 feet

Step-by-step explanation:

Your dad is designing a new garden for your backyard. He has 20 feet of fencing to go around the garden.

Let the width is x.

Length is 2 1/2 feet longer than the width i.e. (x+2 1/2) = (x+2.5) feet

Perimeter = 20 feet

2(l+b) = 20

(l+b) = 10

(x+2.5+x) = 10

2x+2.5 = 10

2x = 7.5

x = 3.75 feet

Length = (x+2.5)

= (3.75+2.5)

= 6.25 feet

So, the length of the garden is 6.25 feet.

3 0

3 years ago

1, 3,4,5,11, answer is 65 _ + (_-_)^2 +_x_

Y_Kistochka [10]

Answer:

1 + (11-4)^2 +3x5

Step-by-step explanation:

1 + (11-4)^2 +3x5

1 + (7)^2 + 3 x 5

1 + 49 + 15

50 + 15 = 65

5 0

3 years ago

30 POINTS FOR SIMPLE QUESTION

Komok [63]

-4 = y + 3

y = -4x - 3

Solve for Y in the first equation:

-4 = y +3

Subtract 3 from both sides:

y = -7

Now using the addition method:

rewrite the second equation as 4x+y = -3

Multiply y = -7 by - 1 to get -y = 7

Now add the two together:

4x +y = -3

-y =7

4x = 4

Divide each side by 4:

x = 4/4 = 1

Then replace x in one of the equations to solve for y which is -7

X = 1, Y = -7

5 0

3 years ago

Which additional fact proves that ΔRST and ΔWXY are congruent if ∠T ≅ ∠Y and RT ≅ WY?

sergejj [24]

Answer:

Hence, option A is correct.

Step-by-step explanation:

We are asked to find the fact such that ΔRST and ΔWXY are congruent.

Since, we are given: ∠T ≅ ∠Y and RT ≅ WY.

we are given the following assumptions:

∠W = x + 5

∠X = 3x - 9

∠Y = 2x + 4

as we are given one angle congruent and one side congruent so in order to prove two triangles are congruent we just need to show that one more pair of angles are congruent.

so from the two triangle we could have that ∠W≅∠R

and ∠X≅∠S

Now we will go by options:

if ∠S=2x+20 then as ∠X≅∠S.

3x-9=2x+20

x=29

∠S=∠W=78°.

if ∠R = 2x + 20 then as ∠W≅∠R

⇒ x+5=2x+20

⇒ x= -15 which is not possible as it will make measure of angle W negative (x+5= -15+5= -10)

if ∠S=2x^2+5 then as ∠X≅∠S.

⇒ 3x-9=2x^2+5

⇒ 2x^2-3x+14=0

on solving this quadratic equation we will get complex zeros.

Hence, option (C) is not correct.

if ∠R = 2x

+ 5 then as ∠W≅∠R.

⇒ x+5=

+ 5

⇒ 2x^2-x=0

⇒ x(2x-1)=0

either x=0 or x=1/2 which is not possible.

because by putting this x value in all the angles we see that sum of all the angles of a triangle is not equal to 180°

Hence, option D is not possible.

Hence, option A is correct.

4 0

3 years ago

A rectangle has a perimeter of 30 and a length of 10. Find the width.

bonufazy [111]

Answer:

Step-by-step explanation:

8 0

2 years ago