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WITCHER [35]
3 years ago
12

Factor the expression, and use the factors to find the x-intercepts of the quadratic relationship it represents. Type the correc

t answer each box, starting with the intercept with the lower value The x- intercepts occur where x = and x =
Mathematics
1 answer:
Kryger [21]3 years ago
6 0

Answer:

The x-intercepts of the quadratic equation: x = -1 , x = -2/3

See explanation below

Step-by-step explanation:

The question is incomplete as the quadratic equation is missing. I would show you how to find the x intercept of a quadratic equation using the factors

Quadratic equation is in the form: ax² + bx + c =0

Where a, b and c are constant

Let's consider the quadratic equation below to solve the question:

2x² + 5x + 3 = 0

By Factoring the expression: (+2) + (+3) = 5; (+2) ×(+3) = 6

2x² + 2x +3x + 3 = 0

2x(x+1) +3(x+1) = 0

(2x + 3) (x+1) = 0

(2x + 3) and (x+1) are the factors of the quadratic equation.

We would equate both to zero to find x-intercepts

2x + 3 = 0 or x+1= 0

2x = -3 or x = -1

x = -2/3 or x = -1

The x-intercepts of the quadratic equation: x = -2/3 or x = -1

The The x-intercepts of the quadratic starting with lower value:

x = -1 , x = -2/3

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5 0
4 years ago
Plz help don’t understand
saul85 [17]

Answer:

Step-by-step explanation:

every time x goes up 1,  y goes up 4  

x = 3  minus x = 2  is a delta (a change of 1)

x = 4  minus x = 3  is a delta (a change of 1)

x = 5  minus x = 4  is a delta (a change of 1)

       the delta x is ALWAYS 1 for this table you can always substract x's to find the delta     delta is symbolized by Δ      Δx  for the delta x

y = 7  minus y = 3  is a delta (a change of 4)

y = 11  minus y = 7  is a delta (a change of 4)

y = 15  minus y = 11  is a delta (a change of 4)

    the delta y is ALWAYS 4 for this table you can always substract y's to find the delta     delta is symbolized by Δ     Δy  for the delta y

the slope m = Δy / Δx      m = 4 / 1     m = 4

     y = mx + b             when x = 0    then  y = b   (called the y intercept)

so how do we find the y intercept?    

look at the pattern in the TABLE  Δx  and Δy

   when x = 1    y = (3 - 4)  = -1

             x = 0    y =( -1 - 4)   = -5

so       y = 4x - 5     is a line equation for the data in this table

                                I believe there are other forms for linear equations

                               I chose the y-intercept form

use the point slope equation

       (y - y1)  =  m(x - x1)            where (x1, y1)  are the coordinates of a point on  

                                                the line

       when you know the slope of the line and a point on the line

       as before

       m = (y2 - y1)  / (x2 - x1)          from the table

           = (7 - 3) / (3 - 2)                 still equals

           = 4/1  =  4        

        pick a point on the line    say x= 4 and y = 11    (4, 11)

       (y - y1)  =  m(x - x1)    

        y - 11   =   4(x - 4)              point slope form

         solving point slope form  for  y

        y  - 11  =   4x - 16               add 11 to both sides    

           y  =  4x - 5                    back to the y-intercept form

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