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Nonamiya [84]
3 years ago
6

The sum of a number and five

Mathematics
1 answer:
VMariaS [17]3 years ago
6 0
The answer would be 10
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Bryce wrote a six-page essay for his English class. It took him 2.5 hours to write the essay. How many minutes did he average pe
erastovalidia [21]
The average per page will be given by:
(number of pages)/(time)
number of pages=6 pages
time=2.5 hours
thus
average=(6/2.5)=2.4 pages per hour
The answer is: 2.4 pages per hour
7 0
3 years ago
Solve for d: 7d = –35
34kurt
7d = - 35
d = - 5

anything 2 ask please pm me
5 0
2 years ago
A box has a square base with each side measuring 8 inches. The height of the box is 4 inches. What is the surface area of the bo
Dafna1 [17]

Answer:

The surface area should be 256 cubic inches

Step-by-step explanation:

The equation you use to find surface area is A=(wl+hl+hw)*2. The w stands for width (8) the l stands for length (8) and the h stands for height (4). When we put these numbers into the equation we get A=(8·8+4·8+4·8)*2. We do the multiplication first, then we add all of them up and times by 2; this gives us our answer of 256.

hope this helps:)

plz can i get brainliest.

3 0
2 years ago
There are 10 soccer teams at the sunnydale soccer league. Each team will play every other team once. How many games will there b
Roman55 [17]

Answer:

90 games

Step-by-step explanation:


6 0
2 years ago
Prove the following statement.
gayaneshka [121]

Answer:

You can prove this statement as follows:

Step-by-step explanation:

An odd integer is a number of the form 2k+1 where k\in \mathbb{Z}. Consider the following cases.

Case 1. If k is even we have: (2k+1)^{2}=(2(2s)+1)^{2}=(4s+1)^{2}=16s^2+8s+1=8(2s^2+s)+1.

If we denote by m=2s^2+2 we have that (2k+1)^{2}=8m+1.

Case 2. if k is odd we have: (2k+1)^{2}=(2(2s+1)+1)^{2}=(4s+3)^{2}=16s^2+24s+9=16s^{2}+24s+8+1=8(2s^{2}+3s+1)+1.

If we denote by m=2s^{2}+24s+1 we have that (2k+1)^{2}=8m+1

This result says that the remainder when we divide the square of any odd integer by 8 is 1.

6 0
3 years ago
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