suppose the people have weights that are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Find the probability that if a person is randomly selected, his weight will be greater than 174 pounds?
Assume that weights of people are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Mean = 177
standard deviation = 26
We find z-score using given mean and standard deviation
z = 
= 
=-0.11538
Probability (z>-0.11538) = 1 - 0.4562 (use normal distribution table)
= 0.5438
P(weight will be greater than 174 lb) = 0.5438
Answer:
7,620,650
Step-by-step explanation:
___________
Answer:
I think A is the answer
but D is the correct answer "kunno"
Step-by-step explanation:
hope it helps :)
The pharmacy should charge $201.6 for the entire bottle
Cost price refers the price the seller bought the product
Selling price refers to the price the seller sells to the consumer.
Profit refers to the money earned by the seller above the cost price
Loss refers to the money paid by the seller above the cost price.
Profit= SP-CP
CP=30X$4.60=$138
TOTAL EXPENSES=$138+30X$1.40
= $180
FOR PROFIT OF 12%,the seller must sell in= $180(1+12/100)
=$201.6
Therefore,the pharmacy should charge $201.6 for the entire bottle to make a profit of atleast 12%
Learn more about profit and loss,
brainly.com/question/19104371
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