Question

Which equation represents a line that passes through (-2, 4) and has a slope 71

Answer 1

Step-by-step explanation:

The point-slope of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

We have the slope m = 71 and the point (-2, 4).

Substitute:

$y-4=71(x-(-2))\\\\\bold{y-4=71(x+2)}$

The slope-intercept form of an equation of a line:

$y=mx+b$

Convert:

$y-4=71(x+2)$         use the distributive property

$y-4=71x+142$         add 4 to both sides

$\bold{y=71x+146}$

The standard form of an equation of a line:

$Ax+By=C$

Convert:

$y=71x+146$            subtract 71x from both sides

$-71x+y=146$        change the signs

$\bold{71x-y=-146}$

The general form of an equation of a line:

$Ax+By+C=0$

Convert:

$71x-y=-146$           add 146 to both sides

$\bold{71x-y+146=0}$