Ask question

Ask question

All categories

3 years ago

14

Would appreciate some help here, thanks!

1 answer:

Arte-miy333 [17]3 years ago

3 0

You know what's the answer calculate it

You might be interested in

Two competing gyms each offer childcare while parents work out. Gym A charges $9.00 per hour of childcare. Gym B charges $0.75 p

Aleks [24]

Answer:

11000 JY.

Step-by-step explanation:

According to today's exchange rate

1 US dollar = 110 JY

100 US dollars = 100 * 110 JY

You should get 11000 JY.

Pick the answer that is closest to this exchange rate.

8 0

2 years ago

Using the cross multiplication method, which of the following is the solution to 11/(2x+5) = 12/2x?

garri49 [273]

Answer:

x = -30 so it's D

Step-by-step explanation:

7 0

3 years ago

Blank percent of 50 shirts is 35 shirts

kirill [66]

$x\% \times 50 = 35 \\ \dfrac{x}{100} \times 50 = 35 \\ x = 35 \div 50 \times 100 \\ x = 70$

Answer check :
$50 \times \dfrac{70}{100} \\ = 35$

Answer : 70%

Hope this helps. - M

4 0

3 years ago

Which name accurately describes the figure shown below and why?

cestrela7 [59]

Answer:

quadrilateral, trapezoid

Step-by-step explanation:

ummmmmmm knowledge is my explanation :)

6 0

3 years ago

Read 2 more answers

The Great Pyramid in Giza, Egypt, is a square pyramid. The dimensions of the pyramid at the time of its completion are shown in

ryzh [129]

Answer:

Area of square pyramid is $153883.8\ m^{2}$ .

Step-by-step explanation:

Diagram of the given scenario is shown below,

Given that,

The Great Pyramid in Giza, Egypt is a square pyramid. The area of base shape is made up with square is $154 \ m^{2}$ . The side of the square is $230 \ m$ and The height of each triangle is $187 \ m$ .

So, Area of Square shape = $154 \ m^{2}$

Side of square = $230 \ m$

Height of each triangle = $187 \ m$

Finding the Height of triangular shape which is here known as slant height.

In Δ ABO, applying Right angle pythagorean Theorem,

Base $(BO)$ = $\frac{230}{2} = 115\ m$

Height $(AO)$ = $187\ m$

Now,

∴ $AB^{2} = AO^{2} \ + \ BO^{2}$

⇒ $AB= \sqrt{AO^{2} \ + \ BO^{2} }$

⇒ $AB= \sqrt{187^{2} \ + \ 115^{2} }$

⇒ $AB= \sqrt{34969 \ + \ 13225 }$

⇒ $AB= 219.53 \ m$

Then,

Area of square pyramid = $area \ of \ square + \ 4\times area \ of \ traiangle$

= $side\times side + 4\times\frac{1}{2}\times AB\times Base$

= $230\times 230 \ + 2\times 219.53\times 230$

= $52900 + 100983.8$

= $153883.8 \ m^{2}$

Hence, Area of square pyramid is $153883.8\ m^{2}$ .

6 0

3 years ago