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3 years ago

What is the factored form of the expression.Factor completely. 56k^3-84k^2+70k-105

Mathematics

2 answers:

kari74 [83]3 years ago

4 0

The answer would be

3x (2x - 3)(x^2 - 6 )

I hope this was helpful :D

PSYCHO15rus [73]3 years ago

3 0

Expression 56k³ - 84k² + 70k - 105 can be simplified to: 7(8k³ - 12k² + 10k - 15)

8k³ - 12k² + 10k - 15 is a third degree expression. it will be factorised to:
(k - 1.5)(k + 2.2)²

Finally expression 56k³ - 84k² + 70k - 105 can be simplified to: 7(k - 1.5)(k + 2.2)²

Good luck

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6th grade math help me, please:)))

Lesechka [4]

Step-by-step explanation:

Hi there!!! 

The answer is option A. 

reason look in picture. 

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3 years ago

What is the area of the composite figure? (use 3.14 for pi). Explain how you arrived at your answer. Please round to the nearest

maksim [4K]

The area of the given diagram is 29.817 square centimeters. The given diagram is combination of rectangle and semi circle.

Step-by-step explanation:

The given is,

Given diagram is combination of Rectangle and Semi circle.

Step:1

Res the attachment,

Area of given diagram = Area of A + Area of B..............(1)

Step:2

For A,

The A section in the given diagram is semi circle,

Diameter of semi circle = Total distance - ( 2+3)

( ∵ 2, 3 are top distance in the given diagram)

$= 10 - 5$

Diameter, d = 5 cm

Radius, $r = \frac{d}{2}$

$r = \frac{5}{2}$

r = 2.5 cm

Area, $A_{A} = \frac {\pi r^{2} }{2}$ ........................(2)

$A_{A} = \frac {\pi (2.5)^{2} }{2}$

$= \frac {\pi ( 6.25) }{2}$

$= \frac{19.63}{2}$

$A_{A} = 9.8174 cm^{2}$

Step:3

For B,

Area of rectangle is,

$A_{B} =lb$ .....................(3)

Where, l - Length = 10 cm

b - Width = 2 cm

Equation (3) become,

$= (10)(2)$

$= 20$

Area of B, $A_{B}$ = 20 $cm^{2}$

Step:4

From the equation (1),

Area of given diagram = 20+ 9.81747

Area = 29.817 square centimeters

Result:

The area of the given diagram is 29.817 square centimeters. The given diagram is combination of rectangle and semi circle.

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3 years ago

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2 years ago

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3 years ago

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$\text{Hey there!}$

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2 years ago