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2 years ago

(BRAINLIEST TO THE PERSON WHO HELPS ME WITH THESE FOUR QUESTIONS)

Mathematics

2 answers:

balandron [24]2 years ago

8 0

Cheryl wrote 7 posts

Nookie1986 [14]2 years ago

3 0

Answer:

Cheryl's posts + 7 posts =Kevin Posts

K-C=7 or C+7+K I use them because C is Cheryl and K is Kevin

Operation=subtraction or addition because it could be K-C=7 or C+7+K

Cheryl wrote K-7=C posts

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Juan recently entered into a contract for a cell phone plan. The table shows the monthly cost in dollars, f(x), if Juan sends x

Delicious77 [7]

Answer:

A linear function is represented

Step-by-step explanation:

The table is:

x f(x)

0 10.00

1 10.02

2 10.04

3 10.06

4 10.08

5 10.10

If we compute the difference between two consecutive function values and we divide it by the difference between their associated x values we get:

(10.02 - 10.00)/(1-0) = 0.02

(10.04 - 10.02)/(2-1) = 0.02

(10.06 - 10.04)/(3-2) = 0.02

(10.08 - 10.06)/(4-3) = 0.02

(10.10 - 10.08)/(5-4) = 0.02

This constant result indicates that a linear function is represented.

5 0

2 years ago

Triangle ABC is congruent to triangle XYZ, as shown below.

il63 [147K]

Answer:

the first answer

Step-by-step explanation:

if a and x are the same and a has an angle of 45 degrees that means that x has an angle of 45 degrees

4 0

2 years ago

Read 2 more answers

Distance from sun in au from mercury pls thanks

mestny [16]

<span>0.39 AU, 36 million miles 57.9 million km

Hope this helps Have good day (:</span>

4 0

2 years ago

Make Q the subject of the formula A = Q2 - 2a.

son4ous [18]

Answer:

$\huge\boxed{Q = \sqrt{A+2a}}$

Step-by-step explanation:

$A = Q^2 -2a$

Adding 2a to both sides

$Q^2 = A+2a$

Taking sqrt on both sides

$Q = \sqrt{A+2a}$

8 0

3 years ago

What is the most precise name for quadrilateral ABCD with vertices A(–5,2), B(–3, 5),C(4, 5),and D(2, 2)?

bonufazy [111]

Answer: ABCD is a parallelogram.

Step-by-step explanation:

First we plot these point on a graph as given in attachment.

From the attachment we can observe that AD || BC || x-axis .

also, AB ||CD, that will make ABCD a parallelogram , but to confirm we check the property of parallelogram "diagonals bisect each other" , i.e . "Mid point of both diagonals are equal".

Mid point of AC= $(\dfrac{-5+4}{2},\dfrac{2+5}{2})=(\dfrac{-1}{2},\dfrac{7}{2})$

Mid point of BD= $(\dfrac{-3+2}{2},\dfrac{5+2}{2})=(\dfrac{-1}{2},\dfrac{7}{2})$

Thus, Mid point of AC=Mid point of BD

i.e. diagonals bisect each other.

That means ABCD is a parallelogram.

8 0

2 years ago