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3 years ago

PLEASE HELP ME I NEED AN ANSWER :( Use the relationship between the angles in the figure to answer the question.

Mathematics

1 answer:

m_a_m_a [10]3 years ago

4 0

The answer is C. x + 49 + 28 = 180

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What is the sum 5/3 +(1/5) please and explain

solmaris [256]

We need to find a common denominator(bottom number of fraction)

5/3 = 25/15 (multiply both top and bottom by 5)
1/5 = 3/15 (multiply both top and bottom by 3)

Now since the denominator is the same we can add to get 25/15 + 3/15 = 28/15

7 0

3 years ago

Read 2 more answers

3.74 to the nearest thousandth

Y_Kistochka [10]

<span>3.7 since the digit after the tenths digit is less than five</span>

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3 years ago

What is the equation of the line that passes through the point (−4,−3) and has a slope of \frac{3}{4}

yawa3891 [41]

Answer:

y = $\frac{3}{4}$ x

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = $\frac{3}{4}$ , then

y = $\frac{3}{4}$ x +c ← is the partial equation

To find c substitute (- 4, - 3) into the partial equation

- 3 = - 3 + c ⇒ c = - 3 + 3 = 0

y = $\frac{3}{4}$ x ← equation of line

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3 years ago

A cyclist travels at an average speed of 17 mph for 2 hours. <br> How far did she travel in miles?

prohojiy [21]

Answer: 34 miles

Step-by-step explanation:

3 0

3 years ago

Find the exact values of a) sec of theta b)tan of theta if cos of theta= -4/5 and sin<0

Gre4nikov [31]

Answer:

Using trigonometric ratio:

$\sec \theta = \frac{1}{\cos \theta}$

$\tan \theta = \frac{\sin \theta}{\cos \theta}$

From the given statement:

$\cos \theta = -\frac{4}{5}$ and sin < 0

⇒ $\theta$ lies in the 3rd quadrant.

then;

$\sec \theta = \frac{1}{-\frac{4}{5}} = -\frac{5}{4}$

Using trigonometry identities:

$\sin \theta = \pm \sqrt{1-\cos^2 \theta}$

Substitute the given values we have;

$\sin \theta = \pm\sqrt{1-(\frac{-4}{5})^2 } =\pm\sqrt{1-\frac{16}{25}} =\pm\sqrt{\frac{25-16}{25}} =\pm \sqrt{\frac{9}{25} } = \pm\frac{3}{5}$

Since, sin < 0

⇒ $\sin \theta = -\frac{3}{5}$

now, find $\tan \theta$ :

$\tan \theta = \frac{\sin \theta}{\cos \theta}$

Substitute the given values we have;

$\tan \theta = \frac{-\frac{3}{5} }{-\frac{4}{5} } = \frac{3}{5}\times \frac{5}{4} = \frac{3}{4}$

Therefore, the exact value of:

(a)

$\sec \theta =-\frac{5}{4}$

(b)

$\tan \theta= \frac{3}{4}$

7 0

3 years ago