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KiRa [710]
3 years ago
10

PLEASE HELP ME I NEED AN ANSWER :( Use the relationship between the angles in the figure to answer the question.

Mathematics
1 answer:
m_a_m_a [10]3 years ago
4 0
The answer is C. x + 49 + 28 = 180
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Expand the following using the Binomial Theorem and Pascal’s triangle. (x + 2)6 (x − 4)4 (2x + 3)5 (2x − 3y)4 In the expansion o
ivolga24 [154]
\bf (2x+3)^5\implies 
\begin{array}{llll}
term&coefficient&value\\
-----&-----&-----\\
1&&(2x)^5(+3)^0\\
2&+5&(2x)^4(+3)^1\\
3&+10&(2x)^3(+3)^2\\
4&+10&(2x)^2(+3)^3\\
5&+5&(2x)^1(+3)^4\\
6&+1&(2x)^0(+3)^5
\end{array}

as you can see, the terms exponents, for the first term, starts at highest, 5 in this case, then every element it goes down by 1, till it gets to 0

for the second term, starts at 0, and every element it goes up by 1, till it gets to the highest

now, to get the coefficient, they way I get it, is "the product of the current coefficient and the exponent of the first term, divided by the exponent of the second term plus 1"

notice the first coefficient is always 1

so...how did we get 10 for the 3rd element?  well, 5*4/2
how did we get 10 for the fourth element?  well, 10*2/4


\bf (2x-3y)^4\implies 
\begin{array}{llll}
term&coefficient&value\\
-----&-----&-----\\
1&&(2x)^4(-3y)^0\\
2&+4&(2x)^3(-3y)^1\\
3&+6&(2x)^2(-3y)^2\\
4&+4&(2x)^1(-3y)^3\\
5&+1&(2x)^0(-3y)^4
\end{array}


\bf (3a+4b)^8\implies 
\begin{array}{llll}
term&coefficient&value\\
-----&-----&-----\\
1&&(3a)^8(+4b)^0\\
2&+8&(3a)^7(+4b)^1\\
3&+28&(3a)^6(+4b)^2\\
4&+56&(3a)^5(+4b)^3\\
5&+70&(3a)^4(+4b)^4\\
6&+56&(3a)^3(+4b)^5\\
7&+28&(3a)^2(+4b)^6\\
8&+8&(3a)^1(+4b)^7\\
9&+1&(3a)^0(+4b)^8
\end{array}

and from there, you can simplify the elements of the expansion by combining the coefficients

like for example, the 7th element of (3a+4b)⁸ will then be 1032192a²b⁶
7 0
3 years ago
Read 2 more answers
1) f(x)=(x - 3)(x - 5)
NemiM [27]

Answer:

Step-by-step explanation:

f(x)= (x - 3)(x - 5)

f(x) = x^2 - 5x - 3x + 15

f(x) = x^2 - 8x + 15

Answer is A

7 0
2 years ago
Solve by factoring.<br><br> m^2+6m+5=0
alina1380 [7]

Answer:

<u>-1 and -5</u>

Step-by-step explanation:

m^2 + 6m + 5 = 0 is factored to: (m + 1)(m + 5) = 0.

The zero product property states that one of the represented parenthesis must equal zero to satisfy the right side of the equation.

(m + 1) = 0

(-1 + 1) = 0

This means that one of the values for m is -1.

(m + 5) = 0

(-5 + 5) = 0

This means that one of the values for m is -5.

<u>Moreover, the value of m by factoring is -1 and -5</u>

3 0
3 years ago
I need the range for this.
docker41 [41]

Answer:

(-3, 3)

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
I need help! I have test tomorrow and I got sick so I couldn’t go to school and I’m lost
Elan Coil [88]
Well 6x8 = 48 so 8 touchdowns is 48 points
7 0
3 years ago
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