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kupik [55]
3 years ago
7

Use the graph below to answer this question:

Mathematics
2 answers:
Morgarella [4.7K]3 years ago
8 0
The answer for this is C . 1
Fittoniya [83]3 years ago
3 0

\bf slope = m = \cfrac{rise}{run} \implies  \cfrac{ f(x_2) - f(x_1)}{ x_2 - x_1}\impliedby  \begin{array}{llll} average~rate\\ of~change \end{array}\\\\ -------------------------------\\\\ \begin{array}{cllll} (\stackrel{x_1}{-3},\stackrel{y_1}{1})\\\\ (\stackrel{x_2}{1},\stackrel{y_2}{5}) \end{array}\begin{cases} x_1=-3\\ x_2=1 \end{cases}\implies \cfrac{f(1)-f(-3)}{1-(-3)}\implies \cfrac{5-1}{1+3}\implies 1

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The difference of six times a number and seven results in 35.
olchik [2.2K]
6x - 7 = 35
6x = 35 + 7            <em>  (add 7 and then divide by 6)</em>
6x = 42
x = 42/6
x = 7

7 0
4 years ago
Read 2 more answers
Which statement describes how the graph of the given polynomial would change if the term -3x6 is adde
Lesechka [4]

Given:

Polynomial is 2x^6+9x^5-7x^3-1.

Term -3x^6 is added in the given polynomial.

To find:

The end behavior of new polynomial.

Solution:

Let, P(x)=2x^6+9x^5-7x^3-1.

New polynomial is

f(x)=2x^6+9x^5-7x^3-1+(-3x^6)

f(x)=(2x^6-3x^6)+9x^5-7x^3-1

f(x)=-x^6+9x^5-7x^3-1

Highest power of x is 6 which is even and leading coefficient is negative. So,

f(x)\to -\infty\text{ as }x\to -\infty

f(x)\to -\infty\text{ as }x\to \infty

Both ends of the graph will approach negative infinity.

Therefore, the correct option is A.

5 0
3 years ago
Help it’s due by 11:59..........................help!
navik [9.2K]

Answer:

1) 7/2

2)DNE i think

3)1/-9

4)5/13 ??

5)1/1

6) 7/-3 ??

Step-by-step explanation:

pretty much the opposite ya know.

5 0
4 years ago
Read 2 more answers
Please help . tjjhhhhhhhh
natka813 [3]

Answer:

19 -  8√3

Step-by-step explanation:

(-4 + √2)^2

= (-4)^2 + 2(-4)(√3) + √3)^2

= 16 - 8√3 + 3

= 19 -  8√3

7 0
4 years ago
Read 2 more answers
Ann wants to choose from two telephone plans. Plan A involves a fixed charge of $10 per month and call charges at $0.10 per minu
Kay [80]
Ann wants to choose from two telephone plans. Plan A involves a fixed charge of $10 per month and call charges at $0.10 per minute. Plan B involves a fixed charge of $15 per month and call charges at $0.08 per minute.

Plan A $10 + .10/minute

Plan B $15 + .08/minute

If 250 minutes are used:

Plan A: $10+$25=$35
Plan B: $15+$20=$35

If 400 minutes are used:

Plan A: $10+$40=$50
Plan B: $15+$32=$47

B is the correct answer. How to test it:

Plan A: $10+(.10*249 minutes)
$10+$24.9=$34.9

Plan B: $15+(.08*249 minutes)
$15+$19.92=$34.92

Plan A < Plan B if less than 250 minutes are used.
4 0
3 years ago
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