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Tamiku [17]
3 years ago
13

The graph represents function 1, and the equation represents function 2: Function 1 A coordinate plane graph is shown. A horizon

tal line is graphed passing through the y-axis at y = 4. Function 2 y = 8x + 12 How much more is the rate of change of function 2 than the rate of change of function 1?
Mathematics
1 answer:
Katena32 [7]3 years ago
7 0
The horizontal line at y=4 doesn't have any slope, so the answer should be relatively easy to find.  It's just the slope of Function 2.

y = 8x + 12 is the function for Function 2.  8x is the important part.

So the rate of change differing from both functions is 8.
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Step-by-step explanation:

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Given:

Vertices of a parallelogram are C(-5,5), D(2,5), E(-1,-1), and H(-8,-1).

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Solution:

We know that, diagonals of a parallelogram always bisect each other. It means the intersection point of the diagonal is the midpoint point of both diagonals.

We can find the midpoint of either diagonal CE or diagonal DH to get the coordinates of intersection point of diagonals, i.e. P.

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P=\left(\dfrac{-5-1}{2},\dfrac{5-1}{2}\right)

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Step-by-step explanation:

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