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Tamiku [17]
3 years ago
13

The graph represents function 1, and the equation represents function 2: Function 1 A coordinate plane graph is shown. A horizon

tal line is graphed passing through the y-axis at y = 4. Function 2 y = 8x + 12 How much more is the rate of change of function 2 than the rate of change of function 1?
Mathematics
1 answer:
Katena32 [7]3 years ago
7 0
The horizontal line at y=4 doesn't have any slope, so the answer should be relatively easy to find.  It's just the slope of Function 2.

y = 8x + 12 is the function for Function 2.  8x is the important part.

So the rate of change differing from both functions is 8.
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All the edges of a regular square pyramid have length 8. find the Volume of the pyramid, Lateral area of the pyramid and the Tot
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Answer:

V = 120.6796

LA = 110.8513

SA = 174.8513

Step-by-step explanation:

Let me know if you need more of an explanation for any of these

First we need the height, one way to find that out is to use the diagonal of the  and one of the diagonal edges of the pyramid.  Specifically we will need half of the diagonal of the square.  We will call the diagonal of the square d.

8^2+8^2=d^2\\d=\sqrt{64+64} \\d=\sqrt{128}

Gonna leave it like that for ease of writing.  So then half of the diagonal is \frac{\sqrt{128}}{2}

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last, we need to find slant height, which we will call s.

(\frac{8}{2})^2+h^2 = s^2\\s=\sqrt{48}

s is also the height of the triangles for purposes of finding area.  Now for the volume and areas.

Volume is area of the base times height divided by 3, so V=8^2\frac{\sqrt{32} }{3}  = \frac{64\sqrt{48} }{3} = 120.6796

Lateral area is the sum of the four areas of the triangles, and each of those are \frac{8*h}{2} so the whole lateral area is 4 times that.  So we get 4\frac{8\sqrt{32} }{2} =110.8513

Total surface area is the lateral surface area + the area of the base, so 110.8513 + 64 = 174.8513

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