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Ganezh [65]
3 years ago
10

If a 25 ft rope is cut into two sections with one section 4 times as long as the other section, how long is the shorter piece?

Mathematics
1 answer:
DaniilM [7]3 years ago
7 0
X = short section of rope
4x = longer section of rope

x + 4x = 25
5x = 25
x = 5

…or in other words the shorter piece of rope is 5 feet long
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The product of two consecutive positive integers is 19 more than their sum. Find the integers.
strojnjashka [21]
The crucial part of the wording of the problem tells us that the two integers are consecutive. So, let's call the first term x. Then the other term must be x + 1 since it comes right after it and is an integer. Now we can solve:

x(x + 1) = x  + (x + 1) + 19

x^2 + x = 2x + 20

x^2 - x - 20 = 0

Now we factor:

(x - 5)(x + 4) = 0

This means x either equals 5 or x = -4 to satisfy the above equation. We know that x is positive from the question itself, so x must be 5. The number consecutively after it then must be 6.
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3 years ago
Solve for m <br> 0.2m=3.5
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Answer:

m = 17.5

Step-by-step explanation:

Given 0.2m=3.5, we want to solve for m.  This involves isolating m on the left side.  To accomplish this, divide both sides by 0.2, obtaining:

m = 3.5/0.2, or m = 17.5

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3 years ago
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kirill [66]

Answer:

5.460

Step-by-step explanation:

6 0
3 years ago
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Chelsea took out three loans for a total of ​$ 78 comma 000 78,000 to start an organic orchard. Her​ business-equipment loan was
lianna [129]

Answer:

Business-equipment loan, A=$15000

Small-business loan, B=$24000

home-equity loan, C= $39000

Step-by-step explanation:

Let the Business-equipment loan at an interest rate of​ 11%=A

Let the​ small-business loan was at an interest rate of 5​% =B

Let her​ home-equity loan was at an interest rate of 4.5​%.=C

Since her total Loan=$78000

A+B+C=78000....(I)

Simple Interest = (P X R X T)/100

Since the Time, T=1 year

Interest on A = 0.11A

Interest on B = 0.05B

Interest on C = 0.045C

The total simple interest due on the loans in one year was ​$4605.

0.11A+0.05B+0.045C=4605....(II)

The annual simple interest on the​ home-equity loan was ​$105 more than the interest on the​ business-equipment loan.

0.045C = 0.11A +105...(III)

We proceed to solve the simultaneous equations.

A+B+C=78000....(I)

0.11A+0.05B+0.045C=4605....(II)

0.045C = 0.11A +105...(III)

From (III), 0.045C = 0.11A +105

Substitute 0.045C = 0.11A +105 into (II).

0.11A+0.05B+0.11A +105=4605

0.22A+0.05B=4500

From (III),

C=\frac{22A}{9}+\frac{7000}{3}

Substitute into (I)

A+B+\frac{22A}{9}+\frac{7000}{3}=78000

\frac{31A}{9}+B=78000-\frac{7000}{3}

\frac{31A}{9}+B=\frac{227000}{3}

\frac{31A+9B}{9}=\frac{227000}{3}

3(31A+9B)=9 X 227000

31A+9B=681000

0.22A+0.05B=4500 (Multiply by 9)

31A+9B=681000 (Multiply by 0.05)

1.98A+0.45B=40500

1.55A+0.45B=34050

Subtracting

0.43A=6450

A=$15000

From (III)

C=\frac{22A}{9}+\frac{7000}{3}

C=\frac{22X15000}{9}+\frac{7000}{3} =39000

C=$39000

from (I)

A+B+C=78000

15000+B+39000=78000

B=$24000

8 0
3 years ago
What is 6.39 rounded to the nearest tenths?
posledela
6.4 is the answer to your question 


4 0
3 years ago
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