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Katen [24]
3 years ago
9

Use logb^2=.4307 and logb^3 - .6826 to evaluate logb18

Mathematics
1 answer:
katrin2010 [14]3 years ago
7 0

Log b 18 = logb 2 * 3 * 3

When multiplying logs, they are added together so:

logb 2 * 3 * 3 = logb 2 + logb 3 + logb 3

Logb 2 is given as 0.4307 and logb 3 is 0.6826

Now we have 0.4307 + 0.6826 + 0.6826 = 1.7959

Logb 18 = 1.7959

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