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4 years ago

Can someone please help me out

Mathematics

2 answers:

victus00 [196]4 years ago

5 0

It’s D.
Since it measures 39 degrees and the other side looks about the same amount, and 39 times 2 is 78.

ira [324]4 years ago

4 0

$BD \: is \: the \: bisector \: of \: \widehat{ABC} \Rightarrow \widehat{ABD}=\widehat{CBD} \\\Rightarrow \widehat{ABC} = \widehat{ABD} + \widehat{CBD} = 2\widehat{ABD} = 2 \times 39 = 78° \\ \Rightarrow D. \: 78°$

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If allopurinol is available in 100 mg tablets, how many tablets are needed to fill a 30 day supply

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3 years ago

A researcher wishes to conduct a study of the color preferences of new car buyers. Suppose that 50% of this population prefers t

ehidna [41]

Answer:

The probability that more than a third of the buyers would prefer brown is 0.8491.

Step-by-step explanation:

This is binomial problem with n=15 and p=0.50.

The binomial formula of probaility is:

P(X=x)= $\frac{n!}{x!(n-x)!} p^{x} (1-p)^{n-x}$

More than a third of the buyers: 15÷3=5

We have to find P(x>5).

P(x>5) = 1 - P(x≤5) = 1 - P(x=0) - P(x=1) - P(x=2) - P(x=3) - P(x=4) - P(x=5)

P(x=0)= $\frac{15!}{0!15!} (0.5)^{0} (1-0.5)^{15}$ =0.00003

P(x=1)= $\frac{15!}{1!14!} (0.5)^{1} (1-0.5)^{14}$ =0.00046

P(x=2)= $\frac{15!}{2!13!} (0.5)^{2} (1-0.5)^{13}$ =0.00320

P(x=3)= $\frac{15!}{3!12!} (0.5)^{3} (1-0.5)^{12}$ =0.01389

P(x=4)= $\frac{15!}{4!11!} (0.5)^{4} (1-0.5)^{11}$ =0.04165

P(x=5)= $\frac{15!}{5!10!} (0.5)^{5} (1-0.5)^{10}$ =0.09164

P(x>5) = 1 - P(x≤5)= 1- 0.00003 - 0.00046 - 0.00320 - 0.01389 - 0.04165 - 0.09164 = 0.8491

4 0

3 years ago

Please help me <br>i really want to know the answer<br>and the explanation for this problems

puteri [66]

Answer:

M = 4.33885225095

Step-by-step explanation:

Area of the square ABFE = 10² = 100

M = 100 - (2P + Q)

Let’s calculate 2P + Q :

The area 2P + Q = area ΔABC + area of sector ACE + area of sector BCF

Note :

ΔABC is an equilateral triangle

m∠CBF = m∠CAE = 30°

area ΔABC = (CG × AB)÷2 = (8.660254037844×10)÷2 = 43.30127018922

CG = √(10^2 - 5^2)=8.660254037844 (Pythagorean theorem)

area of sector BCF = area ΔACE = 100π ÷ 12 = (8.333333333333)π

then

Area 2P + Q = area ΔABC + area sector ACE + area sector BCF

= 43.30127018922+(100÷12)π+(100÷12)π

= 43.30127018922+ (8.333333333333)π + (8.333333333333)π

= 95.66114774905

Conclusion:

M = 100 - (2P + Q) = 100-95.66114774905 = 4.33885225095

8 0

3 years ago