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djverab [1.8K]
3 years ago
14

PLEASE CAN SOMEONE HELP ME WITH THIS!

Mathematics
2 answers:
Anton [14]3 years ago
8 0

Answer:

5^6

5^6 is the common factor so we take 5^7 with 5^6 and we get 5 and 1 = 6

so it’s 5^6

nexus9112 [7]3 years ago
6 0

First solve the addition part:

5^7 + 5^6 =

78125 + 15625 = 93750

Now divide the total by 6:

93750 / 6 = 15625

Because the answer is a whole number ( no decimal) it is divisible by 6.

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z varies jointly with x and y. When x = 2 and y = 3, z = 60. What is the value of z when x = 4 and y = 9?
kondor19780726 [428]
2 x 3 = 6 x 10 = 60
<em>Assuming that you are using the same rule:
</em><em>4 x 9 x 10 = 360
</em>The value of z when x = 4 and y = 9 is 360. Hope this helped!
6 0
3 years ago
Read 2 more answers
Find the area of the shape shown below ​
Arlecino [84]

Answer: 12.5

Step-by-step explanation:

area= 1/2 (2.5+7.5) 2.5

sorry if its not clear enough i dont really know how else to explain it

7 0
3 years ago
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Help please.......... ​
Paha777 [63]
1. Arc KL = 23
2. Arc LON = 203
3. Arc OM = 113
4. Arc KNL = 180
5. 157

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5 0
3 years ago
What goes in the empty boxes?! HELP
Andre45 [30]
I think the left is 8
4 0
3 years ago
Write the point slope form of the line that passes through (-8,2) and is parallel to a line with a slope of -8. include all your
Juli2301 [7.4K]

<u>Answer: </u>

The point slope form of the line that passes through (-8,2) and is parallel to a line with a slope of -8 is 8x + y + 62 = 0

<u>Solution: </u>

The point slope form of the line that passes through the points \left(x_{1} y_{1}\right) and parallel to the line with slope “m” is given as  

y-y_{1}=m\left(x-x_{1}\right) --- eqn 1

Where “m” is the slope of the line.  

x_{1} \text { and } y_{1} are the points that passes through the line.

From question, given that slope “m” = -8

Given that the line passes through the points (-8,2).Hence we get

x_{1}=-8 ; y_{1}=2

By substituting the values in eqn 1, we get the point slope form of the line which is parallel to the line having slope -8 can be found out.

y-2=-8(x-(-8))

On simplifying we get

y – 2 = -8(x +8)

y – 2 = -8x -64

y – 2 +8x +64 = 0

8x + y +62 = 0

Hence the point slope form of given line is 8x + y +62 = 0

7 0
3 years ago
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