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olga2289 [7]
3 years ago
5

6-(-12)= 1/2 ÷ 3/4= Plz answer quickly!

Mathematics
1 answer:
muminat3 years ago
4 0

6-(-12)=18

1/2 ÷ 3/4=2/3

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Mackenzie has $70 in a savings account. The interest rate is 5%, compounded annually.
sladkih [1.3K]

Answer:

She will have $73.5 in 1 year

Step-by-step explanation:

She has $70 and the interest rate is 5% so we need to add 5% to the initial value

x = $70 + $70 * 5%

5% = 5/100

x = $70 + $70 * 5/100

x = $70 + $3.5

x = $73.5

She will have $73.5 in 1 year

8 0
3 years ago
Elise and her dad are planning to attend the state fair. An adult ticket is $21.00. The price of an adult ticket is $10.00 more
belka [17]

Answer:

C)two thirds x + 10 = 21

Step-by-step explanation:

The equation for determining how much it would be paid for the student tickets is shown below:

Given that

The ticket of an adult is $21

Now let us assume the price of the student ticket be x

So two third would be 2 ÷ 3x

And for adult it would be

2 ÷ 3x + 10

Now the equation is

2 ÷ 3x + 10 = 21

So after solving this the option c is correct

And the rest of the options are wrong

6 0
3 years ago
Dude is making 12 pounds of nut mixture with macadamia nuts and almonds. Macadamia nuts cost $9 per pound and almonds cost $5.25
pshichka [43]

Number of pounds of macadamia nuts is 8 pounds and number of pounds of almonds is 4 pounds.

<u>Step-by-step explanation:</u>

Step 1:

Given total pounds of mixture = 12 pounds, cost of macadamia nuts per pound = $9, cost of almonds per pound = $5.25, total cost of mixture per pound = $7.75.

Let number of pounds of macadamia nuts be x and number of pounds of almonds be 12-x.

Step 2:

Form an equation using the above information.

⇒ 9x + 5.25 (12-x) = 12 × 7.75

⇒ 9x + 63 - 5.25x = 93

⇒ 9x - 5.25x = 30

⇒ 3.75x = 30

⇒ x = 8

Number of macadamia nuts is 8 pounds.

Step 3:

Calculate number pounds of almonds

⇒ Number of pounds of almonds = 12 - x = 4 pounds.

5 0
3 years ago
Solve without a calculator log_4(20)-log_4(45)+log_4(144)
AfilCa [17]
Log₄20-log₄ 45+log₄144=
log₄(20/45)+log₄144=                        (log_a b- log_a c=log_a  (b/c) )
log₄[(20*144)/45]=                             (log_a b +log_a c=log_a (b*c) )
log₄(2880/45)=
log₄(64)=n     ⇔      4^n=64                (log_a x=n   ⇔ a^n=x)

4^n=4³      ⇒n=3                                 (64=4*4*4=4³)

Answer: log₄20-log₄ 45+log₄144=3

5 0
3 years ago
Solve x^4 - 3x^2 +2 = 0 using substitution.
Leona [35]

Answer:

x = ± 1 , x = ± \sqrt{2}

Step-by-step explanation:

Let u = x² , then

x^{4} - 3x² + 2 = 0 , can be expressed as

u² - 3u + 2 = 0 ← in standard form

(u - 1)(u - 2) = 0 ← in factored form

Equate each factor to zero and solve for u

u - 1 = 0 ⇒ u = 1

u - 2 = 0 ⇒ u = 2

Change the variable u back to x

x² = 1 ( take square root of both sides )

x = ± 1

or

x² = 2 ( take square root of both sides )

x = ± \sqrt{2}

4 0
2 years ago
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