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seropon [69]
3 years ago
12

*someone that knows math*Solve for m and check your solution. 5/7m = -55

Mathematics
1 answer:
Mamont248 [21]3 years ago
7 0
Your answer would be m= -77
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Fernando ran 3 times as far as Aaron. They ran a total of 12 miles . how many miles did Fernando run?
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4, since Fernando ran 3 times as far as Aaron, and 4 x 3 is 12
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Order these least to greatest, -6.6, 5.8, -6 3/4, 27/5, -5 5/8
svetoff [14.1K]

Answer:

-6 3/4,-6.6,-5 5/8, 5.8,27/5

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4 years ago
What is the factored form of 4x2 + 16x?
bearhunter [10]

Answer:

4x(x+4)

Step-by-step explanation:

both 4x^2 and 16x are divisible by 4x so that's what we'll factor out:

\frac{4x^2}{4x} =x

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so now we have our two factored numbers we will put 4x on the outside of the parentheses since that's what we factored our numbers by.

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Hope this helps!

5 0
4 years ago
The two triangles shown are congruent.<br> Find the value of x
shusha [124]

Answer:

x = 11

Step-by-step explanation:

right triangle ABC

using Pythagoras' identity

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ST = BC , that is

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4 0
2 years ago
A group issimpleif it has no nontrivial proper normal subgroups. LetGbe a simple group of order168. How many elements of order 7
stepladder [879]

Answer:

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Step-by-step explanation:

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And for this case we can use the Sylow theorems, given by:

Let G a group of order p^{\alpha} m  where p is a prime number, with m\leq 1 and p not divide m then:

1) Syl (G) \neq \emptyset

2) All sylow p subgroups are conjugate in G

3) Any p subgroup of G is contained in a Sylow p subgroup

4) n(G) =1 mod p

Using these theorems we can see that 7 = 1 (mod7)

By the theorem we can't have on one Sylow 7 subgroup so then we need to have 8 of them.

Every each 2 subgroups intersect in a subgroup with a order that divides 7. And analyzing the intersection we can see that we can have 6 of these subgroups.

So then based on the information we can have 6*8=48 groups with elements of order 7 in G of size 168

3 0
3 years ago
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