what is the volume of a right cylinder which has a base radius of 14 inches and a height of 2 inches?

Use the properties of logarithms to expand the following expression as much as possible. Simplify any numerical expressions that

malfutka [58]

Answer:

$3+2(log_{2}(x+1) )$

Step-by-step explanation:

First simplify the quadratic present $8(x^{2}+2x+1)=8(x+1)^{2}$

$log_{2}8+log_{2}(x+1)^{2}$

⇒ $3+2(log_{2}(x+1) )$

7 0

4 years ago

We nendndhdhebdbdbdd

astraxan [27]

Step-by-step explanation:

Joe mama

8 0

3 years ago

Read 2 more answers

Suppose you deposit $1200 into a savings account that compounds interest continuously at 3.9%. You left your money in the accoun

kodGreya [7K]

Answer: you would have $1772 at the end of 10 years.

Step-by-step explanation:

The formula for continuously compounded interest is

A = P x e (r x t)

Where

A represents the future value of the investment after t years.

P represents the present value or initial amount invested

r represents the interest rate

t represents the time in years for which the investment was made.

e is the mathematical constant approximated as 2.7183.

From the information given,

P = $1200

r = 3.9% = 3.9/100 = 0.039

t = 10 years

Therefore,

A = 1200 x 2.7183^(0.039 x 10)

A = 1200 x 2.7183^(0.39)

A = $1772 to the nearest dollar

4 0

4 years ago

A store has 80 modems in its inventory, 30 coming from source A and the remainder from source B. Of the modems from source A, 20

Lelu [443]

Answer:

A

Step-by-step explanation: Just use divide them and then add

7 0

4 years ago

A certain medical test is known to detect 73% of the people who are afflicted with the disease Y. If 10 people with the disease

Setler [38]

The probability of an event is the measurement of the chance of that event's occurrence. The probabilities of considered events are:

P(At least 8 have the disease) ≈ 0.4378
P(At most 4 have the disease) ≈ 0.0342

<h3 /><h3>How to find that a given condition can be modeled by binomial distribution?</h3>

Binomial distributions consist of n independent Bernoulli trials. Bernoulli trials are those trials that end up randomly either on success (with probability p) or on failures( with probability 1- p = q (say))

Suppose we have random variable X pertaining to a binomial distribution with parameters n and p, then it is written as

X = B(n,p)

The probability that out of n trials, there'd be x successes is given by

P(X=x) = $^nC_xp^x(1-p)^{n-x}$

Since 10 people can be either diseased or not and they be so independent of each other (assuming them to be selected randomly) , thus, we can take them being diseased or not as outputs of 10 independent Bernoulli trials.

Let we say

Success= Probability of a diseased person tagged as diseased by the clinic

Failure = Probability of a diseased person tagged as not diseased by the clinic.

Then,

P(Success) = p = 72% = 0.72 (of a single person)

P(Failure) = q = 1-p = 0.28

Let X be the number of people diagnosed diseased by the clinic out of 10 diseased people. Then we have: X ≈ B(n+10,P=0.73)

Calculating the needed probabilities, we get:

a) P(At leased 8 have disease) = P(X≥8) =P(X=8) + P(X=9) + P(X=10)

P(X≥8) = $^{10}C_8(0.73)^8(0.28)^2+^{10}C_9(0.73)^9(0.27)^1+^{10}C_{10}(0.73)^{10}(0.27)^0$

P(X≥8) ≈ 0.2548 + 0.1456 + 0.0374 ≈ 0.4378

b) P(At most 4 have the disease) = P(X≤4) = P(X=0) + P(X=1)+P(X=2)+P(X=3)+P(X=4)

P (X ≤ 4) =

$^{10}C_0(0.73)^0(0.27)^{10}+^{10}{C_1(0.73)^1(0.27)^9+^{10}{C_2(0.73)^2(0.27)^8+^{10}C_3(0.73)&^3(0.27)^7 \\$

$+^{10}C_4(0.73)^4(0.27)^6$

P (X ≤ 4) = 0.000003 + 0.000076+0.00088+0.00604+0.02719

P (X ≤ 4) = 0.0342

Thus,

The probabilities of considered events are:

P(At leased 8 have disease) = 0.4378 approx
P(At most 4 have the disease) = 0.0342 approx

Learn more about binomial distribution here:

brainly.com/question/13609688

#SPJ1

4 0

2 years ago