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3 years ago

What percent of an object's earth weight is its weight on mars and oon the moon

2 answers:

6 0

(A) Mars - 37.7% The Moon - 16.6%

(B) An expression you could use for Mars - x * 0.377; For The Moon- x* 0.166 

(C) Neil Armstrong's suit weighed 29.88 pounds 

(D) On Jupiter, Neil Armstrong's suit weighed 425.5 pounds

lina2011 [118]3 years ago

3 0

Answer:

Step-by-step explanation:

(A) Mars - 37.7% The Moon - 16.6% (B) An expression you could use for Mars - x * 0.377; For The Moon- x* 0.166 (C) Neil Armstrong's suit weighed 29.88 pounds (D) On Jupiter, Neil

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Mr jones is planning to pant grass and place afence in a small area for his dog. The rectagular dimension are 12×15 feet. The gr

goldenfox [79]

Answer:

A) The total feet needed for the fence total perimeter is 54 feet

B) The total cost of fence is $432

C) The square feet of grass needed foe the total area is 180 square feet

D) The total cost of the project is $572

Step-by-step explanation:

Given as :

The dimension of rectangular field

Length of rectangular field = L = 12 feet

width of rectangular field = w = 15 feet

The cost of grass per square foot = 50 cents = $0.5 ( ∵ 1 cents = $0.01 )

The cost of small fence = $8 per linear foot

Now, According to question

A ) Let The total feet needed for the fence total perimeter = A feet

∵ Perimeter of rectangular field = 2 × Length + 2 × width

Or, A = 2 × L + 2 × w

Or, A = 2 × 12 feet + 2 × 15 feet

Or, A = 24 feet + 30 feet

∴ A = 54 feet

So, The total feet needed for the fence total perimeter = A = 54 feet

B ) Let The total cost of fence = $B

So, The total cost of fence = The cost of small fence × perimeter of fence

i.e B = $8 × 54 feet

∴ B = $432

So,The total cost of fence = B = $432

C) Let the square feet of grass needed foe the total area = C square feet

∵The Area of rectangular fence = Length × width

Or, The square feet of grass needed foe the total area = Area of rectangular fence = L × w

i.e C = 12 feet × 15 feet

Or, C = 180 feet²

So,The square feet of grass needed foe the total area = C = 180 square feet

D) Let The total cost of grass = $D

∵ The cost of grass per square foot = $0.5

So,Total cost of grass = $0.5 × Area of fence

i.e D = $0.5 × 180 feet²

Or, D = $90

So, The Total cost of grass = D = $90

E) Let the total cost of the project = $E

∵Mr. Jones spend additional $50 for tools

So, The total cost of the project = money spent on tools + total cost of fence + Total cost of grass

i.e E = $50 + B + D

Or, E = $50 + $432 + $90

∴ E = $572

So, The total cost of the project = E = $572

Hence,

A) The total feet needed for the fence total perimeter is 54 feet

B) The total cost of fence is $432

C) The square feet of grass needed foe the total area is 180 square feet

D) The total cost of the project is $572 Answer

3 0

3 years ago

(PLEASE HELP!!!Which number line can be used to find the distance between (-1,2) and (-5,2)?

KIM [24]

Answer:

I think it is the first number line

Step-by-step explanation:

I think it is this one because it is the only one that shows the placement of -1 and -5. I am sorry if the answer is wrong.

6 0

3 years ago

Telemarketing. the probability that a call will reach a live person is 0.2. the calls are independent. (a) a telemarketer places

Sergeeva-Olga [200]

Solution: Telemarketing. the probability that a call will reach a live person is 0.2. the calls are independent. (a) a telemarketer places 5 calls. what is the probability that none of them reaches a live person.

Answer: The given random experiment can be considered as binomial experiment with probability of success = 0.2 and number of trials = 5

Therefore, we have:

$n=5,p=0.2,q=(1-p)=1-0.2=0.8$