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kupik [55]
3 years ago
5

How do I do this please help

Mathematics
1 answer:
Umnica [9.8K]3 years ago
4 0

Answer:

wrong as his calculation was incorrect at initial level itself when he found the result of the division

Step-by-step explanation:

Andre said

3 ÷ \frac{2}{3}

=3 \times \frac{3}{2}

=\frac{3 \times 3}{2}

=\frac{9}{2}

but andre calculated it as

=4\tfrac{1}{3}

=\frac{4 \times 3 + 1}{3}

=\frac{13}{3}

Hence his calculation was incorrect at initial level itself

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Is 10/18 and 45/18 proportional
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3 years ago
Value of the derivative of g(x)=8-10Cosx at 'x=0' is?
VLD [36.1K]

Answer:

g'(0) = 0

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Function Notation

<u>Pre-Calculus</u>

  • Unit Circle

<u>Calculus</u>

  • Derivatives
  • Derivative Notation
  • The derivative of a constant is equal to 0
  • Derivative Property: \frac{d}{dx} [cf(x)] = c \cdot f'(x)
  • Trig Derivative: \frac{d}{dx} [cos(x)] = -sin(x)

Step-by-step explanation:

<u>Step 1: Define</u>

g(x) = 8 - 10cos(x)

x = 0

<u>Step 2: Differentiate</u>

  1. Differentiate [Trig]:                    g'(x) = 0 - 10[-sin(x)]
  2. Simplify Derivative:                   g'(x) = 10sin(x)

<u>Step 3: Evaluate</u>

  1. Substitute in <em>x</em>:                    g'(0) = 10sin(0)
  2. Evaluate Trig:                      g'(0) = 10(0)
  3. Multiply:                               g'(0) = 0
3 0
3 years ago
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