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elena-s [515]
3 years ago
9

What are the factors of the square root of 329

Mathematics
2 answers:
Andru [333]3 years ago
5 0

Answer: x=-\dfrac{3}{2}, 7

Step-by-step explanation:

2x^2-10x-26=x-5

2x^2-10x-26-x+5=0  Move all terms to one side

2x^2-11x-21=0 Simplify 2{x}^{2}-10x-26-x+5

2x^2+3x-14x-21=0 Split the second term

x(2x+3)-7(2x+3)=0  Factor out common terms in the first two terms, then in the last two terms.

(2x+3)(x-7)=0 Factor out the common term 2x+3

x=-\dfrac{3}{2}, 7

daser333 [38]3 years ago
5 0

Answer:

x = -3/4 and 7/2 will be your final answer, but check below for a correction on your work

Step-by-step explanation:

***Your work is incorrect, it should be

2x² - 11x - 21 = 0

you need to subtract an 'x' from both sides, and add 5 to both sides...you added an x to the left side and subtracted a 5 from the left side instead***

I'll solve this so in case you will need help on it too.

Now you'll have

x = (11 ± √[(-11²) - 4(2)(-21)])/([4(2)]

x = (11 ±  √289)/8

x = (11 ± 17)/8

x = (11 + 17)/8 = 28/8 = 7/2

or

x = (11 - 17)/8 = -6/8 = -3/4

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