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3 years ago

WHAT IS 4 TO THE 7TH POWER TIMES NINE

Mathematics

1 answer:

Monica [59]3 years ago

5 0

Answer:

147,456

Step-by-step explanation:

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A city council is deciding whether or not to spend additional money to reduce the amount of traffic. The council decides that it

garri49 [273]

Answer:

t = 2.9272 > 1.708 at 25 degrees of freedom

null hypothesis is rejected

The council decides that it will increase the transportation budget if the amount of waiting time for drivers is not exceeds 18 minutes

Step-by-step explanation:

Step (i):-

A sample of 26 main roads results in a mean waiting time of 21.1 minutes with a sample standard deviation of 5.4 minutes.

Given sample size 'n' = 26

The mean of the sample 'x⁻ = 21.1 min

Standard deviation of the sample 'S' = 5.4 min

The Population mean 'μ' = 18min

Step(ii):-

Null hypothesis: H₀ : The council decides that it will increase the transportation budget if the amount of waiting time for drivers exceeds 18 minutes.

'μ' > 18min

Alternative hypothesis :H₁:

'μ' <18min

Level of significance : ∝=0.05

Degrees of freedom γ = n-1 = 26-1 =25

The test statistic

$t = \frac{x^{-}-mean }{\frac{S}{\sqrt{n} } }$

$t = \frac{21.1-18}{\frac{5.4}{\sqrt{26} } }$

t = 2.9272

Step(iii):-

The tabulated value t = 1.708 at 25 degrees of freedom

t = 2.9272 > 1.708 at 25 degrees of freedom

Null hypothesis is rejected at 5% significance level of significance

Conclusion:-

The council decides that it will increase the transportation budget if the amount of waiting time for drivers is not exceeds 18 minutes

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2 years ago

Let u = ⟨–2, –3⟩ and v = ⟨3, –1⟩. Which graph shows u – v?

sammy [17]

A) The first graph

Correct on Edge

5 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=obtain%20the%20fourier%20expansion%20for%20sin%20ax%20in%20the%20interval%20-%20%7C%20%20%20%5

Norma-Jean [14]

I really do not get it . It’s this a question ? If so can you be a little more specific .

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2 years ago

Write 66² as a product of its prime factors Please ill award brainlist

mestny [16]

Answer:

Step-by-step explanation:

the image above explains it

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2 years ago

Angle 0 lies in the second quadrant and sin 0 = 3/5 cos= coy =

Elza [17]

Consider the right triangle ABC with legs AB=4, AC=3 and hypotenuse BC=5. Angle B has
$\sin B=\frac{opposite}{hypotenuse} = \frac{3}{5}$ and
$\cos B = \frac{adjacent}{hypotenuse} = \frac{4}{5}$ .

Since O lies in second quadrant $\cos O\ \textless \ 0$ and
$\cos O= -\cos B =- \frac{4}{5}$ .
Answer: $\cos O=- \frac{4}{5}$ .

3 0

3 years ago